Answer:
n = -3
Step-by-step explanation:
3(-3 + 3) = 0
3(0) =0
3 x 0 = 0
Answer:
dy/dx = (1 / x^3 + x) × (3x² + 1) × (1/2)
Step-by-step explanation:
y = log[ x² × √(x² + 1) ]
y = log[ √(x(x² + 1)) ]
y = log[ √(x^3 + x) ]
y = log[ √(x^3 + x) ]
Now, let a = √(x^3 + x)
Then y = log(a)
Find dy/da.
y = log(a)
dy/da = (1 / a)
dy/da = (1 / √(x^3 + x))
Find da/dx using chain rule.
a = √(x^3 + x)
Let b = x^3 + x, then a = √b
da/dx = (db / dx) × (da / db)
da/dx = (3x² + 1) × (1/2)× (b)^(-1/2)
da/dx = (3x² + 1) × (1/2)× (x^3 + x)^(-1/2)
Finally, find dy/dx using chain rule.
dy/dx = (dy/da) × (da/dx)
dy/dx = (1 / √(x^3 + x)) × (3x² + 1) × (1/2)×
(x^3 + x)^(-1/2)
dy/dx = (1 / (x^3 + x)) × (3x² + 1) × (1/2)
The farmers had to plough a total of 1,456 acres of land.
Step-by-step explanation:
Step 1; The group of farmers ploughed at a rate of 112 acres of land a day which was 8 acres more than schedule.
Scheduled rate = 112 acres per day - 8 acres = 104 acres per day.
So the farmers were supposed to plough 104 acres a day according to schedule.
Step 2; If the farmers finished a day earlier, it means they had to have completed ploughing 104 acres extra by doing an extra 8 acres a day.
So days took to complete ploughing =
= 13 days.
So in 13 days, they should have ploughed 13 × 104 = 1,352 acres but due to their increased rate, they ploughed 13 × 112 = 1,456 acres in 13 days.
Difference in acres ploughed = 1,456 - 1,352 = 104 acres.
So the farmers ploughed 1,456 acres in 13 days.
Whats the rest of the question?
65 each day because you divide 325 by 5