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grin007 [14]
2 years ago
12

Juan was in debt to his father$4. He then borrowed $3 from his father for lunch. What integer represents Juan's debt to his fath

er?
Mathematics
2 answers:
Yanka [14]2 years ago
4 0
The awnser to this problem is either 12 or 7 by using multiplication or addition
drek231 [11]2 years ago
4 0
He's in $7 debt to his father because he originally had $4 in debt (-4), and now he borrowed $3 (-3), so -4 -3 = -7.
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Where did the Industrial Revolution begin?
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Answer:

england

Step-by-step explanation:

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Combine the like to simplify the expression: -5y + 12 + 8y − 6 − 2 =
ANTONII [103]

First, let's move combine like terms:

-5y + 8y = 6 + 2 -12.

3y = -4.

y = -4/3

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the bike is on sale for $130. if the original price of the bike $200, what is the percent discount ?
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3 years ago
How many years older will you be 1.60 billion seconds from now? (Assume a 365-day year.)
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There are 31,536,000 Seconds in one year

In order to find out how much older you get, you just needed to divide it :

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3 0
2 years ago
This is for algebra 2 can someone tell me if I’m right and can someone explain how do you get a= ?
algol13

Answers:

a = 2

h = 3

k = -3

You have the correct h and k values. Nice work so far.

==========================================================

Explanation:

(h,k) is the vertex. So (h,k) = (3,-3) meaning h = 3 and k = -3

To get the value of 'a', we need to plug in some point on the red graph. Each point is of the form (x,y). We can pick any point we want that isn't the vertex.

Let's pick (0,3) which is the y intercept. I'm picking this because 0 is an easy number to work with

------------

y = a|x-h| + k

y = a|x-3| + (-3) .... plug in the h,k values

y = a|x-3| - 3

3 = a|0-3| - 3 .... plug in (x,y) = (0,3)

3 = a|-3| - 3

3 = a*3 - 3

3 = 3a - 3

3a-3 = 3

3a = 3+3 ... adding 3 to both sides

3a = 6

a = 6/3 ... divide both sides by 3

a = 2

The value a = 2 indicates that the parent function y = |x| has been stretched vertically by a factor of 2. So it is twice as tall as before. Then it has been shifted to place the vertex at (3,-3) as shown in the graph.

------------

You may be wondering why you can't pick on the vertex for (x,y)

Let's see what happens if we use (x,y) = (3,-3)

y = a|x-3| - 3

-3 = a|3-3| - 3 ... plug in (x,y) = (3,-3)

-3 = a|0| - 3 ... uh oh, we get 0 here

-3 = a*0 - 3

-3 = 0 - 3

-3 = -3

We get a true statement, which is nice, but it doesn't tell us anything about what the value of 'a' is. That 'a' term goes away entirely. So I avoided using x = 3 to prevent x-3 from being 0.

4 0
3 years ago
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