<span>B. tiny structures in the cell that carry out the cell's activities</span>
No 6 is common for N and H. 3 is only for H(Hydrogen).
For finding the number of hydrogen atoms we should multiply 6 with 3
So, 6*3 = 18. So there will be 18 hydrogen atoms in 6NH₃
13-13= 0, 19-13= 6, so then 0-6= -6
Answer:
Describe the initial conditions.
The tubing contains
A) starch solution
beaker contains
B) lugol's solution
Describe the final conditions
The tubing contains
C) starch solution and Lugol's solution
beaker contains
A) only Lugol's solution
Explanation:
