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NARA [144]
3 years ago
11

Plz i need help :( write a variable expression that represents the word problem. matt gave q quarters and n nickels to his siste

r. which expression represents the amount in dollars that matt gave to his sister?
a. (0.25+0.05)*qn
b. q*n
c. q+n
d. 0.25q+0.05n
Mathematics
1 answer:
Montano1993 [528]3 years ago
8 0
D is the ANSWER....................................................
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A circle has a radius of three. An arc in the circle has essential angle of 20°. What is the length of the arc
Nataliya [291]

Answer:

1.048

Step-by-step explanation:

<em>(thiter \div 360) \times \pi \times diameter</em>

  1. <em>(20 \div 360) \times \pi \times 6</em>
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3 years ago
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Marizza181 [45]

Answer:

12(3+5)

Step-by-step explanation:

The greatest common factor is 12

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12(3+5)

5 0
2 years ago
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What is the sum of all the integers between 19 and 77
victus00 [196]
Think of it this way: Lets add numbers in pairs, starting at the very outer 2 numbers (19 and 77)  then go in by one and add the second number and the second to last (20 and 76), then (21 and 75) and so on.  The sum of all of these pairs are all the same: 96.  How many 96s will we have?  Well since we're coming from each end toward the middle adding pairs we will have half the distance between 19 and 77, that is (77-19)/2 = 29.  So we can actually just take 96*29 = 2784.  This is the sum of all numbers between 19 and 77
7 0
3 years ago
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Let f(x)=5x3−60x+5 input the interval(s) on which f is increasing. (-inf,-2)u(2,inf) input the interval(s) on which f is decreas
o-na [289]
Answers:

(a) f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing at (-2,2).

(c) f is concave up at (2, \infty)

(d) f is concave down at (-\infty, 2)

Explanations:

(a) f is increasing when the derivative is positive. So, we find values of x such that the derivative is positive. Note that

f'(x) = 15x^2 - 60&#10;

So,

&#10;f'(x) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 15x^2 - 60 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 15(x - 2)(x + 2) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textgreater \  0} \text{   (1)}

The zeroes of (x - 2)(x + 2) are 2 and -2. So we can obtain sign of (x - 2)(x + 2) by considering the following possible values of x:

-->> x < -2
-->> -2 < x < 2
--->> x > 2

If x < -2, then (x - 2) and (x + 2) are both negative. Thus, (x - 2)(x + 2) > 0.

If -2 < x < 2, then x + 2 is positive but x - 2 is negative. So, (x - 2)(x + 2) < 0.
 If x > 2, then (x - 2) and (x + 2) are both positive. Thus, (x - 2)(x + 2) > 0.

So, (x - 2)(x + 2) is positive when x < -2 or x > 2. Since

f'(x) \ \textgreater \  0 \Leftrightarrow (x - 2)(x + 2)  \ \textgreater \  0

Thus, f'(x) > 0 only when x < -2 or x > 2. Hence f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing only when the derivative of f is negative. Since

f'(x) = 15x^2 - 60

Using the similar computation in (a), 

f'(x) \ \textless \  \ 0 \\ \\ \Leftrightarrow 15x^2 - 60 \ \textless \  0 \\ \\ \Leftrightarrow 15(x - 2)(x + 2) \ \ \textless \  0 \\ \\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textless \  0} \text{ (2)}

Based on the computation in (a), (x - 2)(x + 2) < 0 only when -2 < x < 2.

Thus, f'(x) < 0 if and only if -2 < x < 2. Hence f is decreasing at (-2, 2)

(c) f is concave up if and only if the second derivative of f is positive. Note that

f''(x) = 30x - 60

Since,

f''(x) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30x - 60 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30(x - 2) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow x - 2 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow \boxed{x \ \textgreater \  2}

Therefore, f is concave up at (2, \infty).

(d) Note that f is concave down if and only if the second derivative of f is negative. Since,

f''(x) = 30x - 60

Using the similar computation in (c), 

f''(x) \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30x - 60 \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30(x - 2) \ \textless \  0 &#10;\\ \\ \Leftrightarrow x - 2 \ \textless \  0 &#10;\\ \\ \Leftrightarrow \boxed{x \ \textless \  2}

Therefore, f is concave down at (-\infty, 2).
3 0
3 years ago
At what point on the graph of y=2e^X -1 is the tangent line parallel to the line y= 5x -1
IgorLugansk [536]
Paralell has same slope
y=mx+b
m=slope
y=5x-1
when is the slope 5?

take the derivitive of 2e^x
f'(2e^x)=2f'(e^x)=2e^x

that is the slope
5=2e^x
divide both sides by 2
2.5=e^x
take the ln of both sides
ln2.5=x

when x=ln2.5 they are paralell
5 0
3 years ago
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