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Free_Kalibri [48]
3 years ago
15

What's 75% of what number is 24? what's 65% of what number is 39? please answer both

Mathematics
2 answers:
Sholpan [36]3 years ago
8 0

Answer:

Step-by-step explanation:

ion know

n200080 [17]3 years ago
3 0
A) 75/100*X=24 => 3/4*x=24=> X=4*24/3=4*8=32°°°°°° b) 65/100*X=39 => 13/20*X=39 => X=20*39/13 => X=20*3=60 ~~~~~~ Have a nice day!!!!★★
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fomenos

Answer:

18 + 38 = 56 x 16 = 896 divided by 2 = 448cm

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sergejj [24]

Answer:

All of them, I believe.



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Plz help me ...<br> please
r-ruslan [8.4K]

Answer:

x = -1, and y = -2, giving you the answer (-1, -2)

Step-by-step explanation:

In the second equation, we're told that y is equal to 2x.  With that, we can replace "y" in the first one with "2x", giving us:

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-6x = 6

x = -1

Now that we know the value of x, we can simply plug it into the first equation to find y:

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y = -2

So x = -1, and y = -2

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Step-by-step explanation:

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Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that
Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is P(x_1 + x_2 \ge 2 )= 0.5940

Step-by-step explanation:

From the question we are told that

     The rate at which fire breaks out every 10 years is  \lambda  =  1

  Generally the probability distribution function for Poisson distribution is mathematically represented as

               P(x) =  \frac{\lambda^x}{ k! } * e^{-\lambda}

Here x represent the number of state which is  2 i.e x_1 \ \ and \ \ x_2

Generally  the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

          P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 + x_2 \le 1 )

=>        P(x_1 + x_2 \ge 2 ) =  1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]

=>        P(x_1 + x_2 \ge 2 ) =  1 - [ P(x_1  = 0 ,  x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]

=>  P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)

=>    P(x_1 + x_2 \ge 2 ) =  1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}

=>   P(x_1 + x_2 \ge 2 )= 1- [[0.3678  * 0.3679] + [0.3678  * 0.3679] + [0.3678  * 0.3679]  ]

P(x_1 + x_2 \ge 2 )= 0.5940

               

3 0
2 years ago
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