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4 years ago

What's 75% of what number is 24? what's 65% of what number is 39? please answer both

Mathematics

2 answers:

Sholpan [36]4 years ago

8 0

Answer:

Step-by-step explanation:

ion know

n200080 [17]4 years ago

3 0

A) 75/100*X=24 => 3/4*x=24=> X=4*24/3=4*8=32°°°°°° b) 65/100*X=39 => 13/20*X=39 => X=20*39/13 => X=20*3=60 ~~~~~~ Have a nice day!!!!★★

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How many 1/9make up2/3

geniusboy [140]

$\frac{ \frac{2}{3} }{ \frac{1}{9} } =6$

8 0

4 years ago

In the first four months of the year the Gerardos Electric bill were $115.46, $113.38, And $91.25. What was the Gerardos average

gizmo_the_mogwai [7]

Answer:80.02

Step-by-step explanation:

115.46+113.38+91.25= 320.09 /4 months = 80.02

4 0

3 years ago

Read 2 more answers

MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

Step(i):-

By using trigonometry formulas

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

Step(i):-

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

3 0

3 years ago

Need help as soon as possible!

qaws [65]

ANSWER=5.2

EXPLANATION

This triangle shows a example of the Pythagorean Theorem, which means the equation is gonna be

a^2+b^2=c^2

The variables a and b are the straight sides of the triangle, while the variable c  is the curved side on the triangle, or what we are trying to find in this question.

Firstly let’s take the two sides that already have a number shown, also known in the Pythagorean Theorem as sides a and b.

2^2+4.8^2=c^2

Now we want to square the two given numbers to get the equation

4+23.04=c^2

Now we add the two given numbers that we have now squared to get the equation

27.04=c^2

The final step will now be to take the number (27.04) and square root it, which should give you the answer, 5.2

6 0

3 years ago

Convert 23 days to weeks and days?

dezoksy [38]

Answer:

3 weeks and 2 days

Step-by-step explanation:

6 0

3 years ago