All categories

3 years ago

The following polygons are similar: True or False

Mathematics

2 answers:

exis [7]3 years ago

8 0

It is true they are not

stellarik [79]3 years ago

7 0

I would have to say false because they do not have the same perimeter and area

You might be interested in

A trough has ends shaped like isosceles triangles, with width 2 m and height 5 m, and the trough is 18 m long. Water is being pu

fenix001 [56]

9514 1404 393

Answer:

5/9 m/min

Step-by-step explanation:

The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:

2/5 × 2 m = 4/5 m

Then the surface area of the water is ...

A = LW = (18 m)(4/5 m) = 14.4 m²

The rate of change of height multiplied by the area gives the rate of change of volume:

8 m³/min = (14.4 m²)(h')

h' = (8 m³/min)/(14.4 m²) = 5/9 m/min

8 0

3 years ago

Jessica's is making $300 less than four times what she was making when she started working. Let s represent her

vichka [17]

Answer:

4s-300= Jessica's current salary

8 0

3 years ago

Hey can u answer my math question look atbthe picture to see<br> the pic.

Anna35 [415]

Answer:

4 3/4 yards

Step-by-step explanation:

5 1/4 + 2 1/2 = 7 3/4

(1/2 is equal to 2/4)

12 1/2 - 7 3/4 = 4 3/4

Hope this helps, mark me brainliest if it does! :)

4 0

3 years ago

Read 2 more answers

What is the answer of 3m-10=2(4m-5)

mr_godi [17]

3m-10=2(4m-5)
3m-10=8m-10
3m-8m=-10+10
-5m=0
m=0

4 0

3 years ago

Read 2 more answers

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago