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emmasim [6.3K]
3 years ago
7

Question 22 a fruit company delivers its fruit in two types of boxes: large and small. a delivery of 2 large boxes and 3 small b

oxes has a total weight of 83 kilograms. a delivery of 4 large boxes and 8 small boxes has a total weight of 197 kilograms. how much does each type of box weigh
Mathematics
2 answers:
densk [106]3 years ago
7 0
Let <span>L </span>be the weight of a large box and S be the weight of a small box.  So we can set up two equations: 2L + 3S = 834L + 8S = 197 Solve for <span>L </span>or S in one of the equations and substitute it into the other equation and find the other unknown. 2L = 83 - 3SL = (83 - 3S)/2 4(83 - 3S)/2 + 8S = 197166 - 6S + 8S = 1972S = 31
S = 15.5 kg<span>
L = (83 - 3(15.5))/2 = 18.25 kg</span>
olga2289 [7]3 years ago
3 0
Set this up as a system of equations.  The first will be the 2 large boxes plus the 3 small boxes weigh 83 kg, the second will be the 4 large boxes plus the 8 small weigh 197 kg.  2L + 3s = 83  and   4L + 8s = 197.  Solve one of them for either variable.  Let's solve the second one for L:  L = -2s + 49.25.  Sub that value of L into the first equation: 2(-2s + 49.25) + 3s = 83.  Distribute through the parenthesis to get -4s + 98.5 + 3s = 83.  Combine like terms to get -s =-15.5.  or s = 15.5.  So a small box weights 15.5 kg.  A large box is -2(15.5) + 49.5, which is 18.5 kg.
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The x-intercept is the point where the graph cuts the x-axis, and the y-intercept is the point where the graph cuts the y-axis.

The x-axis is the line y = 0 and the y-axis is the line x = 0. To find the intercept between each axis and our graph, we just need to evaluate our function at x = 0 and y = 0.

Calculating the x-intercept, we have

\begin{gathered} x-4\cdot0=8 \\ x=8 \end{gathered}

The x-intercept is (8, 0).

Calculating the y-intercept, we have

\begin{gathered} 0-4y=8 \\ y=-\frac{8}{4} \\ y=-2 \end{gathered}

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10 months ago
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3 years ago
If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
Anestetic [448]

Answer:

Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26

f(1) = 2 - 14 + 38 - 26

f(1) = -12 + 38 = + 26

f(1) = 26 - 26

f(1) = 0

=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

                                 2(x^2 - 6x + 13)

The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16

So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

3 +/- 2i

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