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3 years ago

In triangle VWX, side VW and side XV are congruent and the measure of X is 19 degrees. What is the measure of angle V?

Mathematics

1 answer:

Alchen [17]3 years ago

4 0

Answer:

80.5°

Step-by-step explanation:

Every triangle is measured to be 180°. Subtract X which is 19 from 180

180-19=161

Because V and W are congruent, they are the same length. So you divide 161 by w to get 80.5

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find the volume of a rectangular pyramid with a base of 2 meters by 6 meters and a height of 3 meters (no photo attached)

o-na [289]

Answer:

36 meters^3

Step-by-step explanation:

Formula: Bh

B=Base area

h=height

to find the base area, multiply 2 and 6

2x6 = 12

B=12

and the height is given, so just insert your numbers into the formula

12x3=36

6 0

2 years ago

Carol has eight and 4 3/4 yard of material do you need to use 1/3 material to make a dress how many yards of material will she n

IgorLugansk [536]

Answer:

2 11/12

Step-by-step explanation:

(1/3)×(35/4=35/12=2 11/12 yards

3 0

2 years ago

A rug is to be centered in a room so that the border around it is of a consistent width on all four sides. If the room is 10 ft

aleksley [76]

Answer:

The width of the border can be 9 feet or 3.5 feet.

Step-by-step explanation:

Let the width be x

Length of room = 10 feet

Breadth of room = 15 feet

Length of rug = 10-2x

Breadth of rug = 15-2x

Area of rug = $(10-2x)(15-2x)$

We are given that the area of the rug is 24 square feet.

So, $(10-2x)(15-2x)=24$ ---A

$150-20x-30x+4x^2=24$

$150-24-50x+4x^2=0$

$126-50x+4x^2=0$

$2(x-9)(2x-7)=0$

$x=9,\frac{7}{2}$

$x=9,3.5$

Substitute x =9 in A

$(10-2(9))(15-2(9))=24$

$24=24$

LHS = RHS

Substitute x = 3.5

$(10-2(3.5))(15-2(3.5))=24$

$24=24$

LHS = RHS

So, The width of the border can be 9 feet or 3.5 feet.

7 0

3 years ago

For a process, the average range for all samples was 5 and the process average was 25. If the sample size was 10, calculate UCL

alexira [117]

Answer:

8.885

Step-by-step explanation:

Given that :

Sample size, n = 10

The average range, Rbar for all samples = 5

The upper control limit, UCL for the R-chart is :

UCL L= D4Rbar

From the control chart constant table, D4 = 1.777

Hence,

UCL = 1.777 * 5

UCL = 8.885

The UCL for the R-chart is 8.885

7 0

2 years ago

I need help fast i apperciate

Roman55 [17]

Answer:

Option d is the correct answer.

Step-by-step explanation:

tan A = 24/7

3 0

2 years ago

Read 2 more answers