Hold on just have to type before I can see the question
The second condition tells you that
![t](https://tex.z-dn.net/?f=t)
is half the size of
![u](https://tex.z-dn.net/?f=u)
, so
![t=\dfrac12u](https://tex.z-dn.net/?f=t%3D%5Cdfrac12u)
, which could be rewritten in several ways. In standard form, that would be
![2t-u=0](https://tex.z-dn.net/?f=2t-u%3D0)
.
Answer:
the answer is C (280 square feet)
Step-by-step explanation:
First, cut the lawn so that it becomes two shapes: a rectangle, and a triangle. Solve for both areas.
A(r) = lw
A(r) = (14)(16)
A(r) = 224 square feet
A(t) = bh/2
A(t) = (8)(14) / 2
A(t) = 112 / 2
A(t) = 56 square feet
Add the two areas:
A(r) + A(t) = Area of lawn
224 square feet + 56 square feet = 280 square feet.
Answer:
1
Step-by-step explanation:
8-7=1
Answer:
A =First term of the pattern = 11
To find the first five terms we have to use the rule which is
Add 10 to first term and then subtract 5 from it.Which is equivalent to
= A +10 -5
1. Second Term = 11 + 10 -5
= 21 - 5
=16
→Third term = 16 +10-5
= 26 - 5
= 21
→Fourth term : 21 + 10 - 5
= 31 -5
= 26
→Fifth term : 26 +10 -5
= 36- 5
= 31
→Sixth term:
=31 + 10- 5
= 41 -5
= 36
So, the first five term apart from 11 is 16, 21,26,31,36 which is an Airthmetic progression.