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IgorLugansk [536]
3 years ago
15

This question is worth 4 points: what does the p in the example below mean? (p < .05) the finding has a 95% chance of being t

rue all of these answers are correct the finding has a 5% chance of happening due to chance or random instance this example expresses significance level
Mathematics
1 answer:
Art [367]3 years ago
6 0
I think that it is (0<0.5)
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There are only chickens and pigs in Henry's Barn Henry counted a total of Sixteen animal heads and a total of 50 animal feet.How
raketka [301]

Answer:

9 pigs

Step-by-step explanation:

We have the following numbers of heads:

pigs (p) + chickens (c) = 16 animal heads (1)

And the following numbers of feet:

4p + 2c = 50 animal feet   (2)

From equation (1):

p = 16 - c (3)

By entering equation (3) into (2) we have:

4(16 - c) + 2c = 50

64 - 4c + 2c = 50

c = 7

Now, entering the value of c into equation (3) we have the next value of p:

p = 16 - c

p = 16 - 7

p = 9

Therefore, the number of pigs that Henry has is 9.

I hope it helps you!  

4 0
3 years ago
Find the area of the shape​
Salsk061 [2.6K]

Answer: 12.5

Step-by-step explanation:

you go on the web and google area of trapezium

8 0
4 years ago
Read 2 more answers
Joey and Emily’s teacher gave them each a triangle divided into three parts a,b, and c which looked like the triangle shown belo
polet [3.4K]
We need the photo to answer the question
4 0
4 years ago
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
[20 pts] evaluate the logarithm log(6)1/36​, show work pls!
Delvig [45]

Answer:

\large\boxed{\log_6\dfrac{1}{36}=-2}

Step-by-step explanation:

\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2

\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}

8 0
3 years ago
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