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likoan [24]
3 years ago
5

What value should be added to both sides of the equation X2 +12 X +6 equals -5 to solve the question by completing the square

Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0
X^2 + 12x + 6 = -5
x^2 + 12x = -5 - 6
x^2 + 12x = -11
x^2 + 12x + 36 = -11 + 36.....u add 36 to both sides <=
(x + 6)^2 = 25
x + 6 = (+-) sqrt 25
x + 6 = (+-) 5
x = -6 (+-) 5

x = -6 + 5
x = -1

x = -6 - 5
x = -11

solutions are : x = -1 or x = -11

ur answer : add 36 to both sides.. ur x term is 12, take half of ur x term ,which gives u 6, then u square it, which gives u 36...and add that to both sides
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Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

average=\frac{81+87+x}{3}

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87

This ine72\leq x} \leq 87quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

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Mariulka [41]
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Hope this helps!
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dedylja [7]
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givi [52]

Answer:

The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

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Find GCF(90,75):

Now,

Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

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