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likoan [24]
4 years ago
5

What value should be added to both sides of the equation X2 +12 X +6 equals -5 to solve the question by completing the square

Mathematics
1 answer:
Marta_Voda [28]4 years ago
6 0
X^2 + 12x + 6 = -5
x^2 + 12x = -5 - 6
x^2 + 12x = -11
x^2 + 12x + 36 = -11 + 36.....u add 36 to both sides <=
(x + 6)^2 = 25
x + 6 = (+-) sqrt 25
x + 6 = (+-) 5
x = -6 (+-) 5

x = -6 + 5
x = -1

x = -6 - 5
x = -11

solutions are : x = -1 or x = -11

ur answer : add 36 to both sides.. ur x term is 12, take half of ur x term ,which gives u 6, then u square it, which gives u 36...and add that to both sides
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See the pic below please! AND SHOW WORK!
irinina [24]

Well I don't know !
Let's check out the choices:

A).    3a - 4b = 21,  a=0, b=7

         3(0) - 4(7) = 21

             0  -  28  = 21    Nope.  That's not true.


B).  3a - 4b = 21,  a=-3,  b=2

     3(-3) - 4(-2) = 21

       -9    +  8  = 21

             -1    = 21      Nope.  That's not right.


C).  3a - 4b = 21,    a=-2,  b=-3

      3(-2) - 4(-3) = 21

         -6  + 12  = 21

                 6  =  21          Nope.  That's not it.

Only one choice left.
This one had better be it:

D).  3a - 4b = 21,    a=7,  b=0

       3(7) - 4(0) = 21

         21 -  0    = 21

               21  =  21            Yay !   That's it !
 
7 0
3 years ago
Read 2 more answers
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