If we define "n choose r" as C(n,r)=n!/(r!(n-r)!)
where C(n,r) represents the number of ways (order not important) we can choose r objects out of n, then
Number of ways to choose teachers = 10 choose 2 = C(10,2), and
number of ways to choose students = 41 choose 2 = C(41,2)
So the number of different committees
= C(10,2)*C(41,2)
= 45*820
= 36900
6 is a common multiple of 2 and 3...so Ken is correct
think of multiples like multiplication tables
2 * 1 = 2
2 * 2 = 4
2 * 3 = 6
so 2,4,and 6 are multiples of 2
same with 3..
3 * 1 = 3
3 * 2 = 6
3 * 3 = 9
so 3,6, and 9 are multiples of 3
so 6 is a common multiple of 2 and 3.
factors...they are what can be divided into a number...
6 has factors of 2 and 3....because they both go into 6 evenly
but 6 is not a factor of 2 or 3 because 6 wont go into them evenly
Answer:
substitute the given values for m, n, and p into each problem and solve. Make sure you don't ignore minuses and negatives. Separate with parentheses to make sure you don't get confused.
Step-by-step explanation:
54: -7(-5) - 10( 3/2)
35 - 10(1.5)
35 - 15
20
55. -3mnp
-3 x (-5) x 3/2 x (-8)
15 x 1.5 x (-8)
22.5 x (-8)
-180
56. 8n / (-6p)
8(1.5) / (-6 x -8)
12 / 48
1/4 or .25
57. p squared is (-8)(-8)
2(-8)(-8)(-1.5) / (-5)
128 (-1.5) / (-5)
-192/ (-5) negatives cancel out
192/5
38.4
Answer:
Step-by-step explanation:
let the national average be x
11/100 * x = 11x/100
25.47 - x = 11x/100
100(25.47-x) = 11x
2547 - 100x = 11x
2547 = 11x + 100x
2547 = 111x
x = 2547/111
x = 22.945945945946
22.95
Answer:
The answer is 8.3 repeating. If you round it the answer is 8.