Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
Answer:
(x-2) (x^2 -5)
Step-by-step explanation:
x^3 − 2x^2 − 5x + 10
We will factor by grouping
Take and x^2 out of the first two terms and -5 out of the last two terms
x^2 (x-2) -5(x-2)
Now we can factor out (x-2)
(x-2) (x^2 -5)
Answer:
20
Step-by-step explanation:
4/15 should be your answer!
