Volume of a cube is length * width * height. Because it's a cube, all of these lengths are the same measurement so rather than doing V = l*w*h, we can do one of the measurements cubed, let's call it x.
So Volume = x³. So if we are given the volume, we can the length by doing the cube root.
∛125 = 5
∛216 = 6
Surface area of a cube = 6x². So now we plug both of these measurements into the formula.
For 5:
SA = 6(5)² = 6(25) = 150
For 6:
SA = 6(6)² = 6(36) = 216
The ratio of their surface areas is 150:216 or if you simplify it by dividing both by the GCF of 6, 25:36
Answer:
I'm guessing, say all of them are 20 cm, by the looks of it
Answer:
12/16, 6/8, 15/20, 24/32
Step-by-step explanation:
Because to find the equivalents, you have to multiply/ divide the numerator and the denominator with the same number.
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is:
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore, 2⁵⁰ binary strings of length 50 are there and so it would require:
log₂(2⁵⁰) <span>= 50 bits.
b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:
log2(109)= 29.89
<span> = 30 bits. (rounded to the nearest whole #)
c). </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
log₂(10,4)=log₂(210) = 7.7
= 8 bits. (rounded to the nearest whole #)
Answer:
around 4.1
Step-by-step explanation:
Using Pythaogrean theorem we get <em>sqrt 32</em> or <em>4sqrt2 </em>for the diagonal of the square.
To get x we can use Pythagorean theorem again to set up an equation,
32 + x^2 = 49
This gives us x = <em>sqrt17,</em> which is approximately 4.1231 or around 4.1