Answer: ![\dfrac{1}{10}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B10%7D)
Step-by-step explanation:
Probability =![\dfrac{\text{favorable outcomes}}{\text{total outcomes}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7Bfavorable%20outcomes%7D%7D%7B%5Ctext%7Btotal%20outcomes%7D%7D)
Given : A number cube is tossed and one card is randomly drawn.
Total outcomes for cube = 6
Total outcomes fro cards = 5
Number of yellow cards = 3
Event 1 : drawing 3 on cube .
![P(E_1)=\dfrac{1}{6}](https://tex.z-dn.net/?f=P%28E_1%29%3D%5Cdfrac%7B1%7D%7B6%7D)
Event 2 : drawing a yellow card .
![P(E_2)=\dfrac{3}{5}](https://tex.z-dn.net/?f=P%28E_2%29%3D%5Cdfrac%7B3%7D%7B5%7D)
Since both events are independent then probability of getting 3 on cube and a yellow card is ![P(E_1)\times P(E_2)](https://tex.z-dn.net/?f=P%28E_1%29%5Ctimes%20P%28E_2%29)
i.e. ![\text{P(3, yellow)}=\dfrac{1}{6}\times\dfrac{3}{5}=\dfrac{1}{10}](https://tex.z-dn.net/?f=%5Ctext%7BP%283%2C%20yellow%29%7D%3D%5Cdfrac%7B1%7D%7B6%7D%5Ctimes%5Cdfrac%7B3%7D%7B5%7D%3D%5Cdfrac%7B1%7D%7B10%7D)
Hence, P(3, yellow)= ![\dfrac{1}{10}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B10%7D)