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podryga [215]
4 years ago
15

A number cube is tossed and one card is randomly drawn. Find P(3, yellow) (BTW There are 5 cards 3 yellow 2 blue) The answer cho

ice are: A. 1/30 B. 1/25 C.3/25 D.1/10
Mathematics
2 answers:
adelina 88 [10]4 years ago
5 0
I believe its 1/10 because there are 10 cards 
balandron [24]4 years ago
5 0

Answer: \dfrac{1}{10}

Step-by-step explanation:

Probability =\dfrac{\text{favorable outcomes}}{\text{total outcomes}}

Given : A number cube is tossed and one card is randomly drawn.

Total outcomes for cube = 6

Total outcomes fro cards = 5

Number of yellow cards = 3

Event 1 : drawing 3 on cube .

P(E_1)=\dfrac{1}{6}

Event 2 : drawing a yellow card .

P(E_2)=\dfrac{3}{5}

Since both events are independent then probability of getting  3 on cube and a yellow card is P(E_1)\times P(E_2)

i.e. \text{P(3, yellow)}=\dfrac{1}{6}\times\dfrac{3}{5}=\dfrac{1}{10}

Hence, P(3, yellow)= \dfrac{1}{10}

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The length of a rectangular garden is 7 meters longer than its width. if its perimeter is ( 12 x + 14) meters, find its length i
cluponka [151]
L=7+w
P=(12x+14)=2(6x+7)
l+w= P/2 = 2(6x+7)/2= 6x+7
l+w=6x+7
2l = 6x+7
l = (6x+7)/2
l=7+w
-> w= l-7
= [(6x+7)/2] -7
= (6x+7-14)/2
= (6x-7)/2

7 0
3 years ago
An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
First one to Answer it correctly gets 5 stars :)
faust18 [17]

Answer:

im not the best but i think 200 or 400 m

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Someone please help me​
GalinKa [24]
Answer:

A. 9 sqrt 2

Explanation:

Plug in hypotenuse and given side into
a^2 + b^2 = c^2 and solve.
8 0
3 years ago
Here jwu4444 thank u so much
Galina-37 [17]

Answer:

0

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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