Answer:
A = 121 pi in^2
Step-by-step explanation:
The circumference is given by
C = 2 * pi*r
22 pi = 2 * pi *r
Divide each side by 2 pi
22 pi / (2 pi) = 2 pi r / (2pi)
11 = r
Now find the area
A = pi r^2
A = pi (11)^2
A = 121 pi in^2
Gradient =(y1-y2) / (x1-x2)
(-6-8)/(6-8)
:7
y:mx+c
8:7(8)+c
c:-48
y:7x-48
Answer:
Ratio = 5/3
The ratio (larger to smaller) of the perimeters is 5/3
Step-by-step explanation:
Attached is an image of the two triangles.
Since both triangles are similar, the ratio of their perimeter is equal to the ratio of each similar sides.
Ratio = P1/P2 = S1/S2
Similar side for triangle 1 S1 = 15ft
Similar side for triangle 2 S2 = 9ft
Substituting the values;
Ratio = 15ft/9ft = 5/3
Ratio = 5/3
The ratio (larger to smaller) of the perimeters is 5/3
Answer:
13.20 teaspoon of fertiliser needed for entire garden.
Step-by-step explanation:
Diameter of the garden = 14.50 ft
Radius of the garden = 7.25 ft
Area
[tex]A=\pi r^2[/text]
[tex]A=\pi \times 7.25 \times 7.25[/text]
[tex]\pi=3.14[/text]
[tex]A=\pi \times 7.25 \times 7.25[/text]
[tex]A=3.14 \times 7.25 \times 7.25[/text]
Hence
[tex]A=165.046[/text]
Area is 165.046 Sq Ft
For 25 sq ft of fields the fertiliser needed = 2 tea spoon
For 1 sq ft of fields the fertiliser needed =
[tex]\frac{2}{25}[/text] tea spoon
For 165.046 sq ft of fields the fertiliser needed =
[tex]\frac{2 \times 165.046 }{25}[/text] tea spoon
For 165.046 sq ft of fields the fertiliser needed = 13.20 tea spoon
<span>Answer:
1. AC = AC [Reflexive property]
2. <A = <C [Corresponding angles are congruent]
3. AD = BC [Parallelogram has two congruent opposite legs]
4. Both triangles are congruent by SAS</span>
