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3 years ago

The circumference of a circle is 23π m. What is the area, in the square meters? Express you answer in terms of pi

Mathematics

2 answers:

seraphim [82]3 years ago

8 0

Answer:

Step-by-step explanation:

The circumference of a circle is 23π

On the other hand, The circumference of a circle = 2×π×r ; where r is the radius.

then

by equating the last two expressions we get: 23π = 2πr then r = 23/2

then

the area = π × r² = (23/2)²×π = (132.25)×π

sesenic [268]3 years ago

6 0

Answer:

132.25π m²

Step-by-step explanation:

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If the edge length of a cube is 11 feet, what is the correct way to write the expression to represent the volume of the cube in

satela [25.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find an equation for the perpendicular bisector of the line segment whose endpoints are (5,-9) and (1,3).

____ [38]

Given coordinates of the endpoints of a line segment (5,-9) and (1,3).

In order to find the equation of perpendicular line, we need to find the slope between given coordinates.

Slope between (5,-9) and (1,3) is :

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{3-\left(-9\right)}{1-5}$

$m=-3$

Slope of the perpendicular line is reciprocal and opposite in sign.

Therefore, slope of the perpendicular line = 1/3.

Now, we need to find the midpoint of the given coordinates.

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

$=\left(\frac{1+5}{2},\:\frac{3-9}{2}\right)$

$=\left(3,\:-3\right)$

Let us apply point-slope form of the linear equation:

y-y1 = m(x-x1)

y - (-3) = 1/3 (x - 3)

y +3 = 1/3 x - 1

Subtracting 3 from both sides, we get

y +3-3 = 1/3 x - 1 -3

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3 years ago