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Leno4ka [110]
3 years ago
15

In the sequence 1, 2, 4, .... an an , every nth term for n > 1 is created by the equation an=a(n?1)?2 an=a(n?1)?2 . by what p

ercent is the 11th term greater than the 9th term in this sequence?
Mathematics
1 answer:
KatRina [158]3 years ago
4 0
Each term is doubled
the equation is a_n=a_1(2)^{n-1} where an=nth term
a1=first term
n=which term

ok

so if the 9th term is x then the 10th term is 2x then 11th is 4x
so how much larger is the 11th term than the 9th term?
4x vs x
it's 4 times bigger or 400%
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Help help help help math math
omeli [17]
<h3>Answer:</h3>

5

<h3>Solution:</h3>
  • First, n*7 can be written as 7n.
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Oliga [24]

Answer:

I think the answer is 22% but I am not sure

Step-by-step explanation:

Percentage solution with steps:

Step 1: We make the assumption that 50 is 100% since it is our output value.

Step 2: We next represent the value we seek with X

Step 3: From step 1, it follows that 100%=50

Step 4: In the same vein, x%=11.

Step 5: This gives us a pair of simple equations:

100%=50(1).

X%=11(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the left hand side of both equations have the same unit; we have

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X = 22%

Step 7: Taking the inverse (or reciprocal) of both sides yields

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The computation of the area of the circle is shown below:

As we know that

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The correct answer should be 1436.76

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