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3 years ago

Which is greater 8 cups or 1 quart

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Im pretty sure its 1 quart

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What is the domain of the function shown in the graph?

lara31 [8.8K]

Answer:

the domain is the possible points on the x axis

Step-by-step explanation:

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3 years ago

What is the value of the expression 2^2 + 4^2 ÷ 2^2? 3 6 8 16

slamgirl [31]

The answer is 8 because you use the order of operations. So it would be 16 divided by 4, then you would do 4+4 which is 8

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3 years ago

The variables A, B, and C represent polynomials where A=x^2, B=3x+2, and C=x-3. What is AB-C^2 in simplest form?

yuradex [85]

Answer:

AB-C^2 = 3x^3 + x^2 + 9

Step-by-step explanation:

AB = (x^2)*(3x+2)= 3x^3 + 2x^2

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AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9

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3 years ago

Read 2 more answers

Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 9x2 y2 and the p

dolphi86 [110]

The vector function is, r(t) = $\bold{ < t,2t^2,9t^2+4t^4 > }$

Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.

First surface is the paraboloid, $z=9x^2+y^2$

Second equation is of the parabolic cylinder, $y=2x^2$

Now to find the intersection of these surfaces, we change these equations into its parametrical representations.

Let x = t

Then, from the equation of parabolic cylinder, $y=2t^2$ .

Now substituting x and y into the equation of the paraboloid, we get,

$z=9t^2+(2t^2)^2 = 9t^2+4t^4$

Now the vector function, r(t) = <x, y, z>

So r(t) = $\bold{ < t,2t^2,9t^2+4t^4 > }$

Learn more about vector functions at brainly.com/question/28479805

#SPJ4

7 0

2 years ago

Water has a specific heat of 4.184 J/g°C and requires 23,000 J of heat to raise the

nasty-shy [4]

Answer:

$m=80.840 kg$

Step-by-step explanation:

Given Data,

Q=23000 J

c=4.184 J/g °c

Δt= 68 °c

m=?

By using this equation,

Q=mcΔt

$23000=m\times 4.184\times 68\\\\m=\frac{23000}{4.184\times68} \\\\\\m=80.840 kg$

3 0

2 years ago