Write the following number in scientific notation 0.0012
1 answer:
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Answer:
The standard deviation for the number of students who work full time = 8.38
Step-by-step explanation:
Given data
Sample size n = 284
No. of students work full time is P = 55 % = 0.55
No. of students who not work full time is Q = 100- 55 % = 45 % = 0.45
The standard deviation is given by
Put all the values in above equation we get
S.D. = 8.38
This is the standard deviation for the number of students who work full time.
Factor a difference of squares:
This reduces to
due to the Pythagorean identity. By the same identity, you have
and you're done.
This reduces to
due to the Pythagorean identity. By the same identity, you have
and you're done.
Your answer was: "g+11 over/ 2x+15 " .
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
{
} ; { 
}.
________________________________________________________
→ {but this would depend on the context — and/or the requirements of the course/instructor.}. Good job!
________________________________________________________
Explanation:
________________________________________________________
Given: g(x) =
;
Find: g(x+5) .
To do so, we plug in "(x+5)" for all values of "x" in the equation; & solve:
________________________________________________________
Start with the "numerator": "(x + 6)" :
→ (x + 5 + 6) = x + 11 ;
__________________________________
Then, examine the "denominator" : "(2x + 5)"
→ 2(x+5) + 5 ;
→ 2(x + 5) = 2*x + 2*5 = 2x + 10 ;
→ 2(x+5) + 5 =
2x + 10 + 5 ;
= 2x + 15 ;
________________________________________________________
→ g(x + 5) =
.
________________________________________________________
Note that the "denominator" cannot equal "0" ;
since one cannot "divide by "0" ;
_______________________________________________________
So, given the denominator: "2x + 15" ;
→ at what value for "x" does the denominator, "2x + 15" , equal "0" ?
→ 2x + 15 = 0 ;
Subtract "15" from each side of the equation:
→ 2x + 15 - 15 = 0 - 15 ;
to get:
→ 2x = -15 ;
Divide EACH SIDE of the equation by "2" ;
To isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = -15 / 2 ;
to get:
→ x = - 7. 5 ;
Your answer was: "g+11 over/ 2x+15 " .
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
{ } ; { }.
________________________________________________________
→ {but this would depend on the context — and/or the requirements of the course/instructor.}. Good job!
________________________________________________________
So; " " .
________________________________________________________
Now, examine the "denominator" from the original equation:
________________________________________________________
→ "(2x + 5)" ;
→ At what value for "x" does the 'denominator' equal "0" ?
→ 2x + 5 = 0 ;
Subtract "5" from each side of the equation:
→ 2x + 5 - 5 = 0 - 5 ;
to get:
→ 2x = -5 ;
Divide each side of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = -5 / 2 ;
→ x = -2.5 ;
→ So; " " .
____________________________________________________
The correct answer is:
____________________________________________________
→ g(x + 5) = ;
{ } ; { }.
____________________________________________________
→ Your answer was: "<span>g+11 over/ 2x+15 " .
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
</span> { } ; { }.
________________________________________________________
→ {but this would depend on the context — and/or the requirements of the course/instructor.}. Good job!
________________________________________________________
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
{
________________________________________________________
→ {but this would depend on the context — and/or the requirements of the course/instructor.}. Good job!
________________________________________________________
Explanation:
________________________________________________________
Given: g(x) =
Find: g(x+5) .
To do so, we plug in "(x+5)" for all values of "x" in the equation; & solve:
________________________________________________________
Start with the "numerator": "(x + 6)" :
→ (x + 5 + 6) = x + 11 ;
__________________________________
Then, examine the "denominator" : "(2x + 5)"
→ 2(x+5) + 5 ;
→ 2(x + 5) = 2*x + 2*5 = 2x + 10 ;
→ 2(x+5) + 5 =
2x + 10 + 5 ;
= 2x + 15 ;
________________________________________________________
→ g(x + 5) =
________________________________________________________
Note that the "denominator" cannot equal "0" ;
since one cannot "divide by "0" ;
_______________________________________________________
So, given the denominator: "2x + 15" ;
→ at what value for "x" does the denominator, "2x + 15" , equal "0" ?
→ 2x + 15 = 0 ;
Subtract "15" from each side of the equation:
→ 2x + 15 - 15 = 0 - 15 ;
to get:
→ 2x = -15 ;
Divide EACH SIDE of the equation by "2" ;
To isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = -15 / 2 ;
to get:
→ x = - 7. 5 ;
Your answer was: "g+11 over/ 2x+15 " .
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
{
________________________________________________________
→ {but this would depend on the context — and/or the requirements of the course/instructor.}. Good job!
________________________________________________________
So; "
________________________________________________________
Now, examine the "denominator" from the original equation:
________________________________________________________
→ "(2x + 5)" ;
→ At what value for "x" does the 'denominator' equal "0" ?
→ 2x + 5 = 0 ;
Subtract "5" from each side of the equation:
→ 2x + 5 - 5 = 0 - 5 ;
to get:
→ 2x = -5 ;
Divide each side of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = -5 / 2 ;
→ x = -2.5 ;
→ So; "
____________________________________________________
The correct answer is:
____________________________________________________
→ g(x + 5) =
{
____________________________________________________
→ Your answer was: "<span>g+11 over/ 2x+15 " .
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
</span> {
________________________________________________________
→ {but this would depend on the context — and/or the requirements of the course/instructor.}. Good job!
________________________________________________________