Answer:
Look above
Step-by-step explanation:
Hopr it helps
Answer:
=2.5×10^-5
Step-by-step explanation:
it's 0.00025
Answer:
135
Step-by-step explanation:
9 c /min = ____ qt / h=135 gt
2 and three because the have the same length and all sides are the same
Answer:
Automated menu
![\bar X= 6.7](https://tex.z-dn.net/?f=%5Cbar%20X%3D%206.7)
![s = 3.045](https://tex.z-dn.net/?f=%20s%20%3D%203.045)
![CV = \frac{s}{\bar X}](https://tex.z-dn.net/?f=%20CV%20%3D%20%5Cfrac%7Bs%7D%7B%5Cbar%20X%7D)
![CV= \frac{3.045}{6.7}= 0.454= 45.4\%](https://tex.z-dn.net/?f=%20CV%3D%20%5Cfrac%7B3.045%7D%7B6.7%7D%3D%200.454%3D%2045.4%5C%25)
Live agent menu
![\bar X= 4.27](https://tex.z-dn.net/?f=%5Cbar%20X%3D%204.27)
![s = 1.125](https://tex.z-dn.net/?f=%20s%20%3D%201.125)
![CV = \frac{s}{\bar X}](https://tex.z-dn.net/?f=%20CV%20%3D%20%5Cfrac%7Bs%7D%7B%5Cbar%20X%7D)
![CV= \frac{1.125}{4.27}= 0.263= 26.3\%](https://tex.z-dn.net/?f=%20CV%3D%20%5Cfrac%7B1.125%7D%7B4.27%7D%3D%200.263%3D%2026.3%5C%25)
So then we can conclude that we have lower variation for the Live agent menu since the coefficient of variation is lower compared to the Automated menu
Step-by-step explanation:
We can solve this by case
Automated menu
Data: 11.7 7.4 3.9 2.9 9.2 6.3 5.5
We can begin calculating the mean with the following formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X= 6.7](https://tex.z-dn.net/?f=%5Cbar%20X%3D%206.7)
Now we can calculate the standard deviation with the following formula:
![s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn-1%7D%7D)
And replacing we got:
![s = 3.045](https://tex.z-dn.net/?f=%20s%20%3D%203.045)
Now we can calculate the coeffcient of variation with this formula:
![CV = \frac{s}{\bar X}](https://tex.z-dn.net/?f=%20CV%20%3D%20%5Cfrac%7Bs%7D%7B%5Cbar%20X%7D)
And replacing we got:
![CV= \frac{3.045}{6.7}= 0.454= 45.4\%](https://tex.z-dn.net/?f=%20CV%3D%20%5Cfrac%7B3.045%7D%7B6.7%7D%3D%200.454%3D%2045.4%5C%25)
Live agent menu
Data: 6.2 2.9 4.4 4.1 3.4 5.2 3.7
We can begin calculating the mean with the following formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X= 4.27](https://tex.z-dn.net/?f=%5Cbar%20X%3D%204.27)
Now we can calculate the standard deviation with the following formula:
![s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn-1%7D%7D)
And replacing we got:
![s = 1.125](https://tex.z-dn.net/?f=%20s%20%3D%201.125)
Now we can calculate the coeffcient of variation with this formula:
![CV = \frac{s}{\bar X}](https://tex.z-dn.net/?f=%20CV%20%3D%20%5Cfrac%7Bs%7D%7B%5Cbar%20X%7D)
And replacing we got:
![CV= \frac{1.125}{4.27}= 0.263= 26.3\%](https://tex.z-dn.net/?f=%20CV%3D%20%5Cfrac%7B1.125%7D%7B4.27%7D%3D%200.263%3D%2026.3%5C%25)
So then we can conclude that we have lower variation for the Live agent menu since the coefficient of variation is lower compared to the Automated menu