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qaws [65]
3 years ago
6

Y\7+6= what does y =

Mathematics
1 answer:
choli [55]3 years ago
5 0
Simple, y can be anything. Because you have no other variable on the other side to use; y can be whatever you want to plug-in to the equation. 
You might be interested in
2x divided by x+5 less than or equal to 0
coldgirl [10]
It is more than 0, because you cancel the x, and you get 2+5, which is 7
4 0
3 years ago
Someone help pleaseeee
qaws [65]

Answer:

Part A = D

Part B = 5 and 50

Step-by-step explanation:

Part A:

area = 5*4x = 20x

so, 100 \leq 20x \leq  1000

Part B:

to leave it only by x, you divide both sides by 20

100/20 = 5, 1000/20 = 50

which 5\leq x\leq 50

7 0
3 years ago
Pls ans both the questions im very confused
lions [1.4K]

Answer:

Step-by-step explanation:

In Δ PQS and ΔPQT

∠QPS = ∠RPT       {Common angle}

∠PSQ = ∠PTR = 90°         {QS & RT are altitude}

QS = RT                            {given}

ΔPQS ≅ ΔPRT               {A A S congruent}

PQ = PS                         {CPCT}

So, PQR is an isosceles triangle.

9)

a) Flas card (I) and (iii) are congruent.

b)  A S A congruent

c) BC ≅ RP

5 0
3 years ago
7 times as much as the sum of 1/3 and 4/5
Jet001 [13]
First of all, you add 1/3 and 4/5, so you get:
\frac{1}{3} +  \frac{4}{5}

To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
\frac{1*5}{3*5} +  \frac{4*3}{5*3}
\frac{5}{15} +  \frac{12}{15}

Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
\frac{5+12}{15}
\frac{17}{15}

That's the sum of 1/3 + 4/5.

Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
\frac{17}{15} *  \frac{7}{1}

In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
\frac{17*7}{15*1}
\frac{119}{15}

Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15. 

Hope this Helps! :D
7 0
3 years ago
Read 2 more answers
14a^8c^9 + 2a^4c^3 [Algebra]
rosijanka [135]

Answer:

im not the best at algebra but

2a+3b+4c

Step-by-step explanation:

subtract

(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

add

=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

then subtract

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

3 0
3 years ago
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