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Sveta_85 [38]
3 years ago
8

Do class limits and class marks make sense for qualitative data classes? Explain

Mathematics
1 answer:
alexdok [17]3 years ago
3 0

Answer: NO, class limits and class marks are not meaningful to qualitative data.

Step-by-step explanation: Qualitative data are non-numerical data. They are collected mostly through observation. They include; sex, name and soon.

Class limits and class marks are groupings used in numerical data (quantitative data). They are not relevant and are meaningless to qualitative data classes as these data class are non- numerical.

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For all of the questions <br>with method <br>thankyou​
Dmitry_Shevchenko [17]

Answer:

(i) 7/10

(ii) 3/10

(iii) 1/5

(iv) Rs 40,000

Step-by-step explanation:

The fraction of the salary spent on food = 1/2

The fraction of the salary spent on rented house fee = 1/5

(i) The fraction spent for both food and rental fee = (1/2) + (1/5) = (5 + 2)/10 = 7/10

(ii) The remainder (rest) of the salary = 1 - 7/10 = 3/10

The fraction of the remainder spent for children's education = 1/3

The fraction of the total salary spent for the children's education = (1/3) × (3/10) = 1/10

(iii) The remaining portion deposited in the bank = 1 - (1/10 + 7/10)) = 2/10 = 1/5

(iv) The amount equal to portion of 1/5 of his salary deposited in the bank is Rs 8000

Let <em>x</em> represent his whole salary, we have;

(1/5) × x = Rs 8,000

x = 5 × Rs 8,000 = Rs 40,000

His whole salary is Rs 40,000.

3 0
3 years ago
HELP ME PLEASEEEEEE ASAP I REPEAT HELPPP
tensa zangetsu [6.8K]

Answer:

b

Step-by-step explanation:

denominator(5) stays the same

multiply 2 by 4 since that is 1 fourth of an hour.

So now its 8/5

5 goes into 8 1 time with 3 leftover

So the 1 is a whole number now

the leftover fraction 3/5

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4 0
2 years ago
If y varies inversely as x and y is 2.5 when x is 6, what is y when x is 4? a. 3.75 b. 1.67 c. 0.1 d. 7.5 Please select the best
REY [17]
Because y varies inversely as x, therefore
y= \frac{k}{x}
where k =  constant.

When x = 6, y = 2.5. Ther efore
\frac{k}{6} = 2.5
Cross multiply.
k = 6 x 2.5 = 15

The equation is
y =  \frac{15}{x}

When x = 4, obtain
y =  \frac{15}{4}= 3.75

Answer: a. 3.75

8 0
3 years ago
Read 2 more answers
Point B has coordinates ​(​1,2​). The​ x-coordinate of point A is -8. The distance between point A and point B is 15 units. What
Xelga [282]

Answer:

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}} (1)

Where:

l_{AB} - Length of the line segment AB.

x_{A}, x_{B} - x-coordinates of points A and B.

y_{A}, y_{B} - y-coordinates of points A and B.

If we know that l_{AB} = 15, x_{A} = -8, x_{B} = 1 and y_{B} = 2, then the possible coordinates of point A is:

\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15

81 + (2-y_{A})^{2} = 225

(2-y_{A})^{2} = 144

2-y_{A} = \pm 12

There are two possible solutions:

1) 2-y_{A} = -12

y_{A} = 14

2) 2 - y_{A} = 12

y_{A} = -10

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

8 0
3 years ago
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