Answer:
(1,-1)
Step-by-step explanation:
There are two of them.
I don't know a mechanical way to 'solve' for them.
One can be found by trial and error:
x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes ! That works ! yay !
For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.
The point is near, but not exactly, <em>x = 0.30990693...
</em>If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>
</em>
1:3 is the ratio to boys and girls. I know that 1/4 must be girls. 3/4 will be boys.
Divide 236 by 4.
236/4= 59
Multiply that by 3.
59*3= 177
177 of the students are boys.
I hope this helps!
~kaikers
Answer:
51 square units
Step-by-step explanation:
First you act like each side is it’s separate rectangle.
Then you would multiply 2 and 4 to get 8, the area of one of the sides. Then you would multiply 2 and 2.5 to get 5, the area of another side. Then 2.5 times 5 to get 12.5, the last side. Now sense every side has a side the same size of itself you would take each answer and multiply it by to to get 8x2=16, 5x2=10, and 12.5x2= 25. You would add together 16, 10, and 25 to get 51 square units, the surface area.
Answer:
Option d
Step-by-step explanation:
Other options are not eligible because
a) Integers are not irrational
b)Whole numbers start from 0 and consists positive integers only.But integers consist negative integers also.
c)Natural number consists of positive integers only.
If the question had been asked as some integers are also, then options b) and c) could have been written . But in this case , it is asked every integer is also.
Thank you!
