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NikAS [45]
3 years ago
11

What is the surface area of a cube with 4m, 4m, and 4m as the l,w, and h

Mathematics
1 answer:
hjlf3 years ago
8 0
Cubes have 6 faces, so to find the answer, you can find the area of one face and multiply it by 6. The area of one face would be 4 × 4 = 16 cm², so then 16 × 6 = 96 cm², which is your answer.

I hope this helps!
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Add the following polynomials, then place the answer in the proper location on the grid. Write answer in descending powers of x.
CaHeK987 [17]

Answer:

-x^5+3x^4+16x^3+7x^2-3x+6

Step-by-step explanation:

Given polynomials are:

x^5-4x^4+7x^3+8, 9x^3+7x^2-10 and -2x^5+7x^4-3x+8

Now we need to add the given polynomials, then place the answer in the proper location on the grid. Also we need to write answer in descending powers of x.

So let's add them by combining like terms:

x^5-4x^4+7x^3+8+9x^3+7x^2-10-2x^5+7x^4-3x+8

-x^5+3x^4+16x^3+7x^2-3x+6

Hence final answer in descending order is -x^5+3x^4+16x^3+7x^2-3x+6

6 0
3 years ago
2. What unit of measure would you use for the volume of water in a bathtub?
JulsSmile [24]

2. You would use liters for a bathtub.

3.You would use milliliters for a medicine capsule.


7 0
3 years ago
Mia saved $95.25 in 3 months. She saved $49.00 in the first month and $7.43 in the second month. How much money did Mia save in
vichka [17]
38.82 if you add them all together they give you 95.25
7 0
3 years ago
Read 2 more answers
4 divided by 5 minus radical 15
forsale [732]
-3.073 that is the correct answer
3 0
3 years ago
PLEASE HELP!!!! 20 POINTS!!!!
galben [10]
These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

r sinθ/2 = t 
(r sinθ / 2)² = t²

4) equal both expressions for t²

r cos θ = (r sin θ / 2 )²

5) simplify

r cos θ = r² (sin θ)² / 4

4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1]  ⇒ r = sinθ + 1


<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
6 0
3 years ago
Read 2 more answers
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