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romanna [79]
2 years ago
12

HELP I need to fine the slope-intercept form. Please it’s a timed assignment I only have two try’s and I already used one

Mathematics
1 answer:
barxatty [35]2 years ago
8 0

Answer:

5. y = -1/2x + 6

6.  y = 1/2x + 150

7. y = 10x + 20

8. y = 25x

Step-by-step explanation:

Look at the y-intercept and eliminate the answers you dont need.

Then find the slope of each.

You might be interested in
The difference between 4,632 and 20,000 is what number?
ycow [4]
We find the difference of the two numbers by subtracting the two numbers given above. It is calculated as follows:

Difference = 20000 - 4632 = 15368

Therefore, the difference between <span>4,632 and 20,000 is 15368.

Hope this answers the question. Have a nice day.</span>
4 0
2 years ago
Read 2 more answers
X - 3y +3=0
Arte-miy333 [17]

Answer:

We know that for a line:

y = a*x + b

where a is the slope and b is the y-intercept.

Any line with a slope equal to -(1/a) will be perpendicular to the one above.

So here we start with the line:

3x + 4y + 5 = 0

let's rewrite this as:

4y = -3x - 5

y = -(3/4)*x - (5/4)

So a line perpendicular to this one, has a slope equal to:

- (-4/3) = (4/3)

So the perpendicular line will be something like:

y = (4/3)*x + c

We know that this line passes through the point (a, 3)

this means that, when x = a, y must be equal to 3.

Replacing these in the above line equation, we get:

3 = (4/3)*a + c

c = 3 - (4/3)*a

Then the equation for our line is:

y = (4/3)*x + 3 - (4/3)*a

We can rewrite this as:

y = (4/3)*(x -a) + 3

now we need to find the point where this line ( y = -(3/4)*x - (5/4)) and the original line intersect.

We can find this by solving:

(4/3)*(x -a) + 3 =  y = -(3/4)*x - (5/4)

(4/3)*(x -a) + 3  = -(3/4)*x - (5/4)

(4/3)*x - (3/4)*x = -(4/3)*a - 3 - (5/4)

(16/12)*x - (9/12)*x = -(4/3)*a - 12/4 - 5/4

(7/12)*x = -(4/13)*a - 17/4

x = (-(4/13)*a - 17/4)*(12/7) = - (48/91)*a - 51/7

And the y-value is given by inputin this in any of the two lines, for example with the first one we get:

y =  -(3/4)*(- (48/91)*a - 51/7) - (5/4)

  = (36/91)*a + (153/28) - 5/4

Then the intersection point is:

( - (48/91)*a - 51/7,  (36/91)*a + (153/28) - 5/4)

And we want that the distance between this point, and our original point (3, a) to be equal to 4.

Remember that the distance between two points (a, b) and (c, d) is:

distance = √( (a - c)^2 + (b - d)^2)

So here, the distance between (a, 3) and ( - (48/91)*a - 51/7,  (36/91)*a + (153/28) - 5/4) is 4

4 = √( (a + (48/91)*a + 51/7)^2 + (3 -  (36/91)*a + (153/28) - 5/4 )^2)

If we square both sides, we get:

4^2 = 16 =  (a + (48/91)*a + 51/7)^2 + (3 -  (36/91)*a - (153/28) + 5/4 )^2)

Now we need to solve this for a.

16 = (a*(1 + 48/91)  + 51/7)^2 + ( -(36/91)*a  + 3 - 5/4 + (153/28) )^2

16 = ( a*(139/91) + 51/7)^2 + ( -(36/91)*a  - (43/28) )^2

16 = a^2*(139/91)^2 + 2*a*(139/91)*51/7 + (51/7)^2 +  a^2*(36/91)^2 + 2*(36/91)*a*(43/28) + (43/28)^2

16 = a^2*( (139/91)^2 + (36/91)^2) + a*( 2*(139/91)*51/7 + 2*(36/91)*(43/28)) +  (51/7)^2 + (43/28)^2

At this point we can see that this is really messy, so let's start solving these fractions.

16 = (2.49)*a^2 + a*(23.47) + 55.44

0 = (2.49)*a^2 + a*(23.47) + 55.44 - 16

0 = (2.49)*a^2 + a*(23.47) + 39.44

Now we can use the Bhaskara's formula for quadratic equations, the two solutions will be:

a = \frac{-23.47  \pm  \sqrt{23.47^2 - 4*2.49*39.4}  }{2*2.49} \\\\a =  \frac{-23.47  \pm  12.57 }{4.98}

Then the two possible values of a are:

a = (-23.47 + 12.57)/4.98  = -2.19

a = (-23.47 - 12.57)/4.98 = -7.23

4 0
2 years ago
Ken paid $12 for two magazines. the cost of each magazines with a multiple of 3. what is the possible prices of the magazines
Ilia_Sergeevich [38]
6$ per magazines because it's a multiple of 3
5 0
3 years ago
Read 2 more answers
All factors of x cubed minus 6x squared plus 11x minus 6
miv72 [106K]

Answer:

Step-by-step explanation:

x³-6x²+11x-6

put x=1

1³-6×1²+11×1-6=1-6=11-6=0

by synthetic division

1| 1 -6  11   -6

|     1  -5    6

|----------------

| 1  -5  6 |0

x²-5x+6=0

x²-2x-3x+6=0

x(x-2)-3(x-2)=0

(x-2)(x-3)=0

x=1

x-1=0

so x³-6x²+11x-6=(x-1)(x-2)(x-3)

6 0
3 years ago
Why resultant magnitude by using Pythagorean theorem is different than using ( x,y )components addition vectors ???
Andreyy89

9514 1404 393

Explanation:

Your different answers came about as a result of an error you made in the Pythagorean theorem calculation.

  √(100 +100) = √200 = 14.142 . . . . same as vector calculation

4 0
2 years ago
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