All categories

3 years ago

Inverse function for y=x^2

Mathematics

1 answer:

Leviafan [203]3 years ago

3 0

Answer:

y= $\sqrt{x}$

Step-by-step explanation:

To find inverse of something, just switch the variables

x=y^2

now try to solve back in terms of y

y= $\sqrt{x}$

You might be interested in

(x+d)(x+e)=x^2+fx+33

victus00 [196]

Answer:

f=14 or f=34

Step-by-step explanation:

(x+d)(x+e) =x^2 +fx+33, d, e, f>0

x^2 +xe+dx+de=x^2+fx+33

x^2+(e+d)x+de=x^2 +fx+33 that

e+d=f and d*e=33, d=33/e

e+33/e=f

33=1*33 or 33=3*11

If e=1,d=33 then f=34

If e=3*,d=11, then f=14

4 0

3 years ago

PLEASE ANSWER FAST! WILL GIVE BRAINLIEST!

NemiM [27]

Answer:

Step-by-step explanation:

You need to find the area of each of the shapes by multiplying the length by the width. Then, you need to add them all together. I won't do it for you because it will make it harder to learn stuff in the future but I told you the formula!!

8 0

2 years ago

Please again sorry help me last one

Bezzdna [24]

Answer:

$3.41

Step-by-step explanation:

262.94 + 83.65 = 346.59

350.00 - 346.59 = 3.41

5 0

3 years ago

Abigail tosses a coin off a bridge into the stream below. The distance, in feet, the coin above the water is modeled by the equa

melomori [17]

Answer:

7 seconds

Step-by-step explanation:

Distance of the coin above the water is modeled by the equation

$y=-16x^2+96x+112$

where $x$ is time taken to cover the distance

Now equating with zero.

$0=-16x^2+96x+112\\\Rightarrow 16x^2-96x-112=0\\\Rightarrow x=\dfrac{-\left(-96\right)\pm \sqrt{\left(-96\right)^2-4\times \:16\left(-112\right)}}{2\times \:16}\\\Rightarrow x=7, -1$

So, time taken by the coin to hit the water is 7 seconds.

6 0

3 years ago

[20 pts] evaluate the logarithm log(6)1/36, show work pls!

Delvig [45]

Answer:

$\large\boxed{\log_6\dfrac{1}{36}=-2}$

Step-by-step explanation:

$\text{We know:}\\\\\log_ab=c\iff a^c=b\\\\\log_6\dfrac{1}{36}\qquad\text{use}\ a^{-1}=\dfrac{1}{a}\\\\=\log_636^{-1}=\log_6(6^2)^{-1}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\log_66^{(2)(-1)}=\log_66^{-2}\qquad\text{use}\log_ab^n=n\log_ab\\\\=-2\log_66\qquad\text{use}\ \log_aa=1\\\\=-2(1)=-2$

$\log_6\dfrac{1}{36}=-2\ \text{because}\ 6^{-2}=\dfrac{1}{6^2}=\dfrac{1}{36}$

8 0

3 years ago