It's A.............................
Given:
Sample Mean <span>= 30<span>
Sample size </span><span><span><span>= 1000</span></span><span>
</span></span></span>Population Standard deviation or <span><span><span>σ<span>=2</span></span><span>
</span></span>Confidence interval </span><span>= 95%</span>
to compute for the confidence interval
Population Mean or <span>μ<span><span>= sample mean ± (</span>z×<span>SE</span>)</span></span>
<span><span>where:</span></span>
<span><span>SE</span>→</span> Standard Error
<span><span>SE</span>=<span>σ<span>√n</span>= 30</span></span>√1000=0.9486
Critical Value of z for 95% confidence interval <span>=1.96</span>
<span>μ<span>=30±<span>(1.96×0.9486)</span></span><span>
</span></span><span>μ<span>=30±1.8594</span></span>
Upper Limit
<span>μ <span>= 30 + 1.8594 = 31.8594</span></span>
Lower Limit
<span>μ <span>= 30 − 1.8594 = <span>28.1406</span></span></span>
<span><span><span>
</span></span></span>
<span><span><span>answer: 28.1406<u<31.8594</span></span></span>
7MM because the prisma is retangular so the answer is c
Answer:
The Susana swam the fastest.
Step-by-step explanation:
<u>Speed</u> : It is defined as the distance traveled per unit time.
<u>Formula used</u> : 
First we have to determine speed of the following persons.
<u>For Tawni :</u>
Distance = 50 m
Time = 40.8 s
1.225 m/s which is the speed of Tawni.
--
<u>For Pepita :</u>
Distance = 100 m
Time = 60.2 s
1.661 m/s which is the speed of Pepita
--
<u>For Susana :</u>
Distance = 200 m
Time = 112.4 s
1.779 m/s which is the speed of Susana
From this we conclude that, in this problem meter affects the response and the speed of Susana is more than the Pepita and Tawani.
Thus, Susana swam the fastest.
It's 8! range is just the greatest value minus the lowest value
(=^_^=)
