Answer:
a
Step-by-step explanation:
20-9=11
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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Answer:
b
Step-by-step explanation:
she took four tests with one more to take totals 5 tests
88 x 5 = 440
all her tests need to equal at least 440 to get an 88 average
since she has 85 average after 4, 85*4 = 340, so her 4 tests so far have equaled 340
440-340 = 100
she will need to get a 100 on her 5th test to have an 88 average
It's D. intersecting lines and lines that have the same equation.
