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Arte-miy333 [17]
4 years ago
5

What is a-2÷5a+a+2÷5a​

Mathematics
1 answer:
Andrej [43]4 years ago
4 0

Answer:

=2a

Step-by-step explanation:

a-2/5a and a+2/5a cancel each other out and your left with a+a aka 2a

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Step-by-step explanation:

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Timber beams are widely used in home construction. When the load​ (measured in​ pounds) per unit length has a constant value ove
Delicious77 [7]

Answer:

a) 0.4

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Step-by-step explanation:

We are given the following information in the question:

The load is said to be uniformly distributed over that part of the beam  between 90 and 105 pounds per linear foot.

a = 90 and b = 105

Thus, the probability distribution function is given by

f(x) = \displaystyle\frac{1}{b-a} = \frac{1}{105-90} = \frac{1}{15},\\\\90 \leq x \leq 105

a) P( beam load exceeds 99 pounds per linear​ foot)

P( x > 99)

=\displaystyle\int_{99}^{105} f(x) dx\\\\=\displaystyle\int_{99}^{105} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{99}^{105} = \frac{1}{15}(105-99) = 0.4

b) P( beam load less than 92 pounds per linear​ foot)

P( x < 92)

=\displaystyle\int_{90}^{92} f(x) dx\\\\=\displaystyle\int_{90}^{92} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{90}^{92} = \frac{1}{15}(92-90) = 0.133

c) We have to find L such that

\displaystyle\int_{L}^{105} f(x) dx\\\\=\displaystyle\int_{L}^{105} \frac{1}{15} dx\\\\=\frac{1}{15}[x]_{L}^{105} = \frac{1}{15}(105-L) = 0.4\\\\\Rightarrow L = 99

The beam load should be greater than or equal to 99 such that the probability that the beam load exceeds L is 0.4.

4 0
4 years ago
What can each term of the equation be multiplied by to eliminate the fractions before solving 1/2x-5/4+2x=5/6+x
Kobotan [32]

Answer:

Multiply each by 12

Step-by-step explanation:

A common multiple is 12

7 0
3 years ago
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