Answer:
x=11.2
Step-by-step explanation:
Answer:
a=x^8
b=^6x
Step-by-step explanation:
i just combine them and got the answer
x^5 x x^2
x^8
y^5 x y
y^6x
Hope it helpsssssssss Because im a snake :)
Hello, The answer to this question is, A. $12.48
As far a domain, you only care about the denominator and radicals.
f(x) = 2 - √x is the denominator, so it can't be 0.
Also x is under a radical, so x can't be negative.
Set the denominator equal to 0 to find the excluded values.
2 - √x = 0
-√x = -2
√x = 2
x = 4, so 4 is an excluded value
The domain is all real numbers greater than or equal to 0, except 4.
[0, 4) U (4, ∞)
0 ≤ x < 4 U x > 4
Answer:
m∠P=140°
Step-by-step explanation:
Given:
∠P and ∠Q are supplementary angles.
The measure of angle P is five less than four times the measure of angle Q.
To find m∠P
Solution:
The measure of angle P can be given as:
A) ![m\angle P=4(m\angle Q-5)](https://tex.z-dn.net/?f=m%5Cangle%20P%3D4%28m%5Cangle%20Q-5%29)
And
B)
[Definition of supplementary angles]
Substituting equation A into B.
![4(m\angle Q-5)+ m\angle Q=180](https://tex.z-dn.net/?f=4%28m%5Cangle%20Q-5%29%2B%20m%5Cangle%20Q%3D180)
Solving for ![m\angle Q](https://tex.z-dn.net/?f=m%5Cangle%20Q)
Using distribution:
![4m\angle Q-20+ m\angle Q=180](https://tex.z-dn.net/?f=4m%5Cangle%20Q-20%2B%20m%5Cangle%20Q%3D180)
Simplifying by combining like terms.
![5m\angle Q-20=180](https://tex.z-dn.net/?f=5m%5Cangle%20Q-20%3D180)
Adding 20 to both sides.
![5m\angle Q-20+20=180+20](https://tex.z-dn.net/?f=5m%5Cangle%20Q-20%2B20%3D180%2B20)
![5m\angle Q=200](https://tex.z-dn.net/?f=5m%5Cangle%20Q%3D200)
Dividing both sides by 5.
![\frac{5m\angle Q}{5}=\frac{200}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B5m%5Cangle%20Q%7D%7B5%7D%3D%5Cfrac%7B200%7D%7B5%7D)
![m\angle Q=40](https://tex.z-dn.net/?f=m%5Cangle%20Q%3D40)
Substituting
in equation B.
![m\angle P+ 40=180](https://tex.z-dn.net/?f=m%5Cangle%20P%2B%2040%3D180)
Subtracting both sides by 40.
![m\angle P+ 40-40=180-40](https://tex.z-dn.net/?f=m%5Cangle%20P%2B%2040-40%3D180-40)
![m\angle P=140](https://tex.z-dn.net/?f=m%5Cangle%20P%3D140)
Thus, we have:
m∠P=140° (Answer)