True because rational numbers are countable, but the irrational numbers are uncountable.
V=u+at
4=u+1a
2=u+2a
subtract
2=-a
a=-2
4=u-2
u=6
v=6-2t
or y=6-2x
or y=-2x+6
The answer would be -8.4.
In both cases there are more than one possible function sutisfying given data.
1. If
- x‑intercepts are (–5, 0), (2, 0), and (6, 0);
- the domain is –5 ≤ x ≤ 7;
- the range is –4 ≤ y ≤ 10,
then (see attached diagram for details) you can build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their maximum and minimum left and right you can obtain another function that satisfies the conditions above.
2. If
- x‑intercepts are (–4, 0) and (2, 0);
- the domain is all real numbers;
- the range is y ≥ –8,
then you can also build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their minimum left and right you can obtain another function that satisfies the conditions above.
Note, that these examples are not unique, you can draw a lot of different graphs of the functions.
Answer: yes, there are more than one possible function
Answer
the length is 20 cm and breadth is 16cm
Step-by-step explanation:
let, 2(a+b)= 72( as its the formulae of circumference)
here a is the length and b is the breadth
now total area is ab
according to the question
a(b-6)= ab-120
or -6a= - 120
so length is 20 cm
now by putting the value in the 1st eq we get
2(a+b)=72
or(a+b)=36
or 20+b=36
so breadth is 16 cm.
length is 20cm and breadth is 16 cm
(u can verify that easily)
thank u