This statement is false. When water is decomposed into hydrogen and oxygen; these gases are in a position of combining again to reform water. Water is a molecule consisting of one atom of oxygen bound to two hydrogen atoms. The atoms are joined by covalent bonds; however they have addition hydrogen bonds between the partial negative oxygen and the partial positive hydrogen atom.
Answer:
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive
Explanation:
A wide range of nuclei are found to be NMR active. NMR is the acronym for nuclear magnetic resonance. It is a powerful spectroscopic tool which uses radio waves. The nuclear spin is described by the nuclear quantum number I and can take on values of; 0,1/2, 1, 3/2,2,5/2 etc.
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive e.g Carbon-12 and Oxygen-16 nuclei.
Commonly, all NMR active nuclei posses I ≥ 1/2, Hydrogen -1 , Carbon-13 and boron-11 are common examples of NMR active nuclei.
I believe it is c electrons fill orbitals in order of increasing orbital energy
M = n / V
Where, M is molarity (M or mol/L), n is number of moles of the solute (mol) and V is volume of the solution (L).
Here the solute is KNO₃.
The given molarity is 1.3 M
This means 1L of solution has 1.3 moles of KNO₃.
Hence moles in 600 mL = 1.3 M x 0.6 L = 0.78 mol
Therefore to make 1.3 M KNO₃ solution, needed moles of KNO₃ is 0.78 mol
