Vibin fjn no longer in the hospital room for the first place and the only thing i could have is the one who is not working with
Answer:
Total percent of customers who order a drink with their entrée = 76%
Step-by-step explanation:
Let
Total customers = 100%
customers who order a meat entrée = 90%
customers who order a vegetarian entrée = 10%
Of the customers who order a meat entrée, 80% order a drink
% of customers who order a meat entrée and drink = 80% of 90%
= (80/100 * 90/100) * 100
= (0.8 * 0.9) * 100
= 0.72 * 100
= 72%
% of customers who order a meat entrée and drink = 72%
Of the customers who order a vegetarian entrée, 40% order a drink.
% of customers who order a vegetarian entrée and drink = 40% of 10%
= (40/100 * 10/100) * 100
= (0.4 * 0.1) * 100
= 0.04 * 100
= 4%
% of customers who order a vegetarian entrée and drink = 4%
What is the percent of customers who order a drink with their entrée?
Total percent of customers who order a drink with their entrée = % of customers who order a meat entrée and drink + % of customers who order a vegetarian entrée and drink
= 72% + 4%
= 76%
Total percent of customers who order a drink with their entrée = 76%
The answer would be 7/3. You would divide them both by 3. You just divide them by the same number to the point were you cant divide both by the same number anymore. For example 18/9 you can divide it by 2 to get 2.
z 5 − z+2 2z+4 =−3 space, startfraction, 5, divided by, z, end fraction, minus, start fraction, 2, z, plus, 4, divided by, z
yan [13]
Answer:
The sum of all the possible values for z that satisfy the above equation is -5.
Step-by-step explanation:
The given equation is
We need to find the sum of all the possible values for z that satisfy the above equation.
The given equation can be rewritten as
Cancel out common factors.
Add 2 on both sides.
Multiply both sides by -1.
Only z=-5 satisfy the given equation.
Therefore the sum of all the possible values for z that satisfy the above equation is -5.
First, you have to represent each given set by listing their elements. Observe:
• D = {x | x is a whole number}
D = <span>ℤ
</span>D = {..., – 3, – 2, – 1, 0, 1, 2, 3, ...}
• E = {x | x is a perfect square between 1 and 9}
("between" does not include the boundaries)
E = {x | x is a perfect square, 1 < x < 9}
E = {x | x = k², k ∈ ℕ and 1 < x < 9}
E = {2²}
E = {4}
• F = {x | x is an even number, 2 ≤ x < 9}
F = {2, 4, 6, 8}
So,
D ∩ F
= {..., – 3, – 2, – 1, 0, 1, 2, 3, ...} <span>∩ {2, 4, 6, 8}
</span>
= {2, 4, 6, 8} ≠ {4, 6}
Therefore, that statement is false.
I hope this helps. =)