Answer:
14, 21, and 63
Step-by-step explanation:
we can set the three unknown numbers as x, y, and z
so
x + y + z =98
now we are given that the first (x) is seven less than the second (y)
x = y - 7
the third number (z) is three times the second (y)
z = 3y
since we have an equation for z and x in terms of y, we can plug it into the first equation and solve for y.
(y-7) + y + (3y) =98
y - 7 + y + 3y =98
y + y + 3y =105
5y = 105
y=21
now that we know y, we can plug its value into either the second or the third equation to find x or z (I chose to find z first)
z = 3y
z = 3(21)
z = 63
now we can plug in y to find x
x = y - 7
x = 21 - 7
x = 14
so the three numbers should be 14, 21, and 63
I think the answer is 19.46
If the function is 
and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.
Given function is and f(4) − f(1) = f '(c)(4 − 1).
In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.
We begin by calculating f(2) and f(5):
f(2)=
f(2)=1
f(5)=
f(5)=1
And the slope of the function:
(x)=
(c)=0
Now,
=-2
=0
-2 is not equal to 0. So there is not any answer.
Hence if the function is and f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.
Learn more about derivatives at brainly.com/question/23819325
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Divide 24 by 4 because the denominator is 4..
24÷4=6
Multiply 6 by 3 because the numerator is 3.
6×3=18
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