19. 5x - 5 = 3x -9
2x = -4
x = -2
19. Answer is A
A method that always works is to find the slope of the given line, then find the negative reciprocal of that. Your result will be the slope of the perpendicular line. Using this slope and the given point, fill in the parameters of the point-slope form of the equation of a line.
For m = slope of given line and (h, k) = given point, the perpendicular line will be
y = (-1/m)(x -h) +k
Often, this equation can be simplified to another appropriate form, such as slope-intercept form (y = mx+b) or standard form (ax+by=c).
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The slope of a given line can be found by solving its equation for y. The slope is the coefficient of x in that solution. If the given line is characterized by two points, (x1, y1) and (x2, y2), then its slope is m = (y2-y1)/(x2-x1).
In the unusual case where the given line is vertical (x=<some constant>), the slope of the perpendicular line is zero, and the line you want becomes y=k.
Answer:
317
Step-by-step explanation:
I did this on khan academy
Answer:
d = 6.997 or 7
Step-by-step explanation:
Use Pythagorean Theorem to find the diagonal of the end of the prism
2^2 + 3^2 = C^2 Simplify
4 + 9 = C^2 Add
13 = C^2 Take the square root of both sides
3.6 = C
Now plug this into the Pythagorean Theorem equation for the diagonal of the whole prism.
3.6^2 + 6^2 = d^2 Simplify
12.96 + 36 = d^2 Add
48.96 = d^2 Take the square root of both sides
6.997 = d This can be rounded up to 7, if needed
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
