Answer:
There are 10 pigs and 30 chickens
Step-by-step explanation:
Let the number of pigs be x
let the number of chickens be y
Then there are 40 heads . So the total number of pigs and chickens is 40
x + y = 40-----------------------(1)
We know that pigs have 4 legs and chickens have 2 legs
4x + 2y = 100----------------------(2)
Solving (1) and (2)
multiply (1) by 2
2x + 2y = 80-------------------------(3)
subtract (3) from (2)
4x + 2y = 100
2x + 2y = 80
----------------------------
2x = 20
----------------------------
![x = \frac{20}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B20%7D%7B2%7D)
x = 10
Now Substituting x in (1), we get
10 + y = 40
y = 40 - 10
y = 30
Answer:
<14, 0>
Step-by-step explanation:
I know this question looks like a pain, but no worries! It's simple operations; just multiplication and addition/subtraction. What this problem has is two vectors, u and v, and it wants you to find the sum of those two vectors after they're multiplied by a scalar. So what this actually looks like is:
-4<-6, 1> + 2<-5, 2>
All you have to do is first distribute that number out front (called a scalar) to the vectors inside.
<24, -4> + <-10, 4>
Adding them isn't as visually straightforward, but what you actually do is combine these two vectors one coordinate at a time. You take 24 and -10 (the two coordinates in the first position of both vectors) and add them. You should get 14. Now do the same with the second position, -4 and 4. If you add those two, you get 0.
Therefore, these two vectors added together gives you the vector <14, 0>.
Answer:
how many does he have???
Step-by-step explanation:
J can find the height of the fifth member on this way
S=150
S1=153
S2=150
S3=151
S4=152
S5=?
S= (s1+s2+s3+s4+s5)/5:
5*150= <span>153+150+151+152+S5
S5=5*150-606=750-606=144
Answer is 144 cm</span>
Answer:
Oof
Step-by-step explanation:
First, change the denominators cuz, math. Then just do the math. Why you asking me?