Tan^5x=tan^3x∗tan^2x
sin^2x+cos^2x=1
tan^2x+1=sec^2x
tan^2x=sec^2x−1
Problem
Determine the functions value when x= -1?
a. g(-1) = -3
b. g(-1) = 0
c. g(-1) = 1
d. g(-1) = 27
Solution
For this case we just need to find the value of g when x= -1 and if we look at the table we got:
g(-1)= (-1)^3 + 6(-1)^2 +12(-1) +8
g(-1)= -1 +6 -12+8 = 5-12+8= 1
And then the solution for this case would be:
c. g(-1) = 1
Answer:
-4∠X≤-1
Step-by-step explanation:
I cant find symbol more, so yeah
x greater that -4 and less or equal to -1
Since, the number w and 0.8 are additive inverses.
A number 'a' is said to have an additive inverse '-a' if "a+ (-a)= 0".
Since, 'w' and '0.8' are additive inverses of each other such that 
Therefore, the value of 'w' should be '-0.8' so that
.
So, the value of 'w' is =0.8
Now, Refer to the attached image which represents the position of 0.8 , w ( that is -0.8) and the sum of 0.8 and w.
Sum of 0.8 and w = 0.8 + w
= 0.8 +(-0.8)
= 0.