ANSWER ASAP!! DUE SOON! ONLY ANSWER IF YOU ARE CORRECT, I CANNOT GET THIS WRONG!!!

Gelneren [198K]

13+13=26
9+9=18
18+26=44

Hope this helps :)

3 0

3 years ago

If the base of a Pyramid has an area of 144sq ft And if the slant higher of the pyramid is 10ft what would be the higher of the

pogonyaev

Answer:

the height of the pyramid is 8 ft

Step-by-step explanation:

Considering the base of the pyramid to be square whose area is 144 sq ft

This means the side of the base would be √144 = 12 ft.

Now, if you will imagine a pyramid we can easily observe that

Height(H) , slant height( L=10 ft) and half of the side length( 6ft) make a right angle triangle. We can easily calculate height from Pythagoras theorem as

10^2 = H^2 +6^2

⇒ H^2 = 10^2-6^2 = 100-36 = 64

⇒ H = 8 ft

Therefore, the height of the pyramid is 8 ft

3 0

3 years ago

A researcher at a large company has collected data on both the beginning salary and the current salary of 48 randomly selected e

Stolb23 [73]

Answer:

dgrfgfgrfsdfsg

Step-by-step explanation:

aeswrfehghfdgsgbgdfhtgrtfdgf

3 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

3 years ago

The sum of three consecutive numbers is 36. What are the numbers?

Yuliya22 [10]

Answer:

11, 12, and 13

Step-by-step explanation:

3 0

3 years ago

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