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Lina20 [59]
3 years ago
8

1/2(2xto the power of 2-8)+1/3(6xto the power of -3)

Mathematics
1 answer:
cluponka [151]3 years ago
5 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------

\bf \cfrac{1}{2}(2x^2-8)+\cfrac{1}{3}(6x^{-3})\implies \cfrac{2x^2-8}{2}+\cfrac{6x^{-3}}{3}\implies \cfrac{2x^2}{2}-\cfrac{8}{2}+\cfrac{6}{3}\cdot \cfrac{1}{x^3}
\\\\\\
x^2-4+2\cdot \cfrac{1}{x^3}\implies x^2-4+ \cfrac{2}{x^3}\implies \cfrac{(x^3\cdot x^2)-(x^3\cdot 4)+2}{x^3}
\\\\\\
\cfrac{x^{3+2}-4x^3+2}{x^3}\implies \cfrac{x^5-4x^3+2}{x^3}
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On Friday, Steven sold 4 pitchers of lemonade from his lemonade stand. On Saturday, he sold 1/3 as much lemonade as on Friday. H
Nutka1998 [239]
1/3 of 4 = 4/3 = 1 1/3
The answer is
1 1/3 pitchers
6 0
3 years ago
.
iren2701 [21]

Answer:

x-5 = 0 has a remainder of 3

x = 5

therefore p(5) = 3

x+8 = 0 has a remainder of 0

x = -8

therefore p(-8) = 0

3 0
3 years ago
What is the solution of the linear-quadratic system of equations? { y = x 2 + 5 x − 3 y − x = 2
svp [43]

The two solutions for the system of equations:

y = x^2+ 5x - 3

y - x = 2

Are:

(-5, -7) and (1, -1)

<h3>How to solve the system of equations?</h3>

Here we have the following system of equations:

y = x^2+ 5x - 3

y - x = 2

We can replace the first equation into the second one to get:

(x^2+ 5x - 3) - x = 2

x^2 + 4x - 3 = 2

x^2 + 4x - 3 - 2 = 0

x^2 + 4x - 5  = 0

Using the quadratic formula, we will get the solutions:

x = \frac{-4 \pm \sqrt{4^2 - 4*1*-5} }{2} \\\\x = \frac{-4 \pm 6}{2}

The two solutions are:

x = (-4 - 6)/2 = -5

x = (-4 + 6)/2 = 1

To find the values of y, we can evaluate the linear equation:

when x = -5

y - (-5) = -2

y + 5 = -2

y = -2 - 5 = -7

So one solution is (-5, -7)

when x = 1

y - 1 = -2

y = -2 + 1 = -1

The other solution is (1, -1)

Learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

5 0
1 year ago
6!/4! ? I. Need help
Licemer1 [7]
\tfrac{6!}{4!}&#10;\newline&#10;&#10;\tfrac{6*5*4*3*2*1}{4*3*2*1}&#10;\newline&#10;&#10;6*5 = 30
8 0
4 years ago
Read 2 more answers
How do i <br> Evaluate 4!.
Wewaii [24]
Hello there!

The formula is
N! = n(n -1)(n - 2)
Now all we have to do is replace N by 4
N! = 4(4-1)(4-2)
    = (4)(3)(4-2)
    = (12)(2)
    = 24 
Here you go, the answer is : 24


I hope this answer help! Good luck with your studies. 

5 0
3 years ago
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