<span>Answers:
(12x^2 + 3x + 6) + (-7x^2 – 4x – 2) = 5x^2 - x + 4
(2x2 – x) + (-x – 2x2 – 2) = -2x - 2
(x3 + x2 + 2) + (x2 – 2 – x3) = 2x^2
(x2 + x) + (x2 + 8x – 2) = 2x^2 + 9x - 2
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-2x(4x² - 5x + 3) Distribute/multiply -2x into (4x² - 5x + 3)
(4x²)(-2x) - (5x)(-2x) + (3)(-2x)
-8x³ + 10x² - 6x
Your answer is the 3rd option
Answer:
This tells us that:
![A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
So we are saying we have scalars, c and d, such that:
.
So we want to find a way to express this as:
Ax=b where x is the scalar vector,
.
So we can write this as:
![\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%267%5C%5C5%26-8%5C%5C3%26-9%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dc%5C%5Cd%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%5C%5C3%5C%5C-15%5Cend%7Barray%7D%5Cright%5D)
(Base x Height) / 2 is the formula
Answer:
I plotted points since i cant draw lines very well with a mouse
Step-by-step explanation: