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horrorfan [7]
3 years ago
13

Am I right or wrong?

Mathematics
1 answer:
omeli [17]3 years ago
8 0

You are absolutely right.

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In triangle ABC, angle A is 75o and angle B is 20o. Select the triangle that is similar to triangle ABC.
Arturiano [62]

Answer:

A. \triangleDEF where \angle D = 75^{\circ} and \angle E = 20^{\circ}.

Step-by-step explanation:

At first we must keep in mind that two triangles are similar when they have same angle configuration, that is, each pair of angles is congruent. If \triangleABC and \triangleDEF, then \angle A \equiv \angle D and \angle B \equiv \angle E. Hence, \angle D = 75^{\circ} and \angle E = 20^{\circ}.

In a nutshell, correct answer is A.

4 0
3 years ago
What is the value of x
dedylja [7]
89 squared. The hypotenuse is equal to 9.434 which is 89 squared.
4 0
3 years ago
Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible. step 1 if a rectangle has dimensions
Veronika [31]


Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and 
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y

x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y. 
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.
7 0
3 years ago
X^2- 4x- 6y- 14=0 in standard parabola form.
uranmaximum [27]
<span>X^2- 4x- 6y- 14=0
6y = x^2 - 4x - 14 
Divide through by 6:-

y = (1/6)x^2 - (2/3)x -  7/3</span>
7 0
3 years ago
Helppp please reallly fasttt!!!
Bingel [31]

Answer:

Step-by-step explanation:

3^{2}+ 7^{2} = EF^{2}

58=EF^{2}

EF=\sqrt{58}

4 0
3 years ago
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