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ANEK [815]
3 years ago
15

What is the molar mass of NH4Cl

Chemistry
1 answer:
adoni [48]3 years ago
6 0
53.491 g/mol

Hope it helps. :)
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What is the ratio of hydrogen(H) to oxygen(O) in hydrogen peroxide(H2O2)?
Alona [7]

Answer: 2:2 but if simplified it’s 1:1

Explanation:

7 0
3 years ago
In order for fission reactions to be successful, they must be self-perpetuating, meaning they must be able to keep themselves go
aleksandrvk [35]

Answer:

Option C is correct.

The minimum amount of material that is needed for a fission reaction to keep going is called the critical mass.

Explanation:

Nuclear fission is the term used to describe the breakdown of the nucleus of a parent isotope into daughter nuclei.

Normally, the initial energy supplied for nuclear fission is the energy to initiate the first breakdown of the first set of radioactive isotopes that breakdown. Once that happens, the energy released from the first breakdown is enough to drive further breakdown of numerous isotopas in a manner that leads to more energy generation.

But, for this to be able to be sustained and not fizzle out, a particular amount of radioactive material to undergo nuclear fission must be present. This particular amount is termed 'critical mass'

Hope this Helps!!!

3 0
3 years ago
Which equation is most likely used to determine the acceleration from a velocity vs. time graph?
Agata [3.3K]

Answer:

is a= delta v over t.

Explanation:

because the history

4 0
3 years ago
Carbon-14 is a radioactive isotope which decays with a half-life of 5730 years. what is the first-order rate constant for its de
marishachu [46]
In chemical equilibrium, radioactive decay occurs because of unstability due to the high neutron-to-proton ratio. Through time, the radioactive element is converted to a new element. This radioactive decay undergoes first order reaction. Its equation is in the form of 

A = A₀e^(-kt), where A is the amount of the element after time t, A₀ is the original amount of element at t=0 and k is the rate constant. 

Half-life is the amount of time for A to be 1/2 of A₀. Modifying the equation during half time, we let A=1/2 A₀. Then.

1/2 A₀ = A₀e^(-kt)
1/2 = e^(-k(5730))
k = 0.000121

Thus, the first-order rate constant is equal to 0.000121 per year.


4 0
3 years ago
Pls help lollollolljdjdjdjdjjdjjzjzjsjsjsis
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