Answer:
A) Nonmetal carbon shares valence electrons with each nonmetal hydrogen forming four covalent bonds.
Explanation:
Methane is formed when nonmetal carbon shares valence electrons with each nonmetal hydrogen forming four covalent bonds. Nonmetals share electrons to form covalent bonds.
Good luck! :)
Answer:
Explanation:
There are two heat flows in this process and, since energy (heat) can neither be destroyed nor created, the energy change for the system must equal zero.
Data:
For Fe, m₁ = ?; C₁ = 0.452 J°C⁻¹g⁻¹; Ti = 2.00 °C; T_f = 21.50 °C
For H₂O, m₂ = 120 g; C₂ = 4.18 J°C⁻¹g⁻¹; Ti = 22.00 °C; T_f = 21.50 °C
Calculations:
1. Temperature changes
ΔT₁ = T_f - Ti = 21.50 °C - 2.00 °C = 19.50 °C
ΔT₂ = T_f - Ti = 21.50 °C - 22.00 °C = -0.50 °C
2. Mass of steel rod
Answer:
6.475 M
Explanation:
Number of moles = 25.9 moles
Volume = 4.00 L
Molarity = ?
The relationship between the quantities is given as;
Molarity = Number of moles / Volume
Molarity = 25.9 / 4
Molarity = 6.475 M
<h2>
Answer:</h2>
Both of them will have same kinetic energy.
<h2>
Explanation:</h2>
- Kinetic energy is the energy of motion, every object in motion posses some kinetic energy.
- Kinetic energy can be calculated by the given formula,
i.e, K.E = 1/2 mv² .
Where, K.E is kinetic energy,
m is mass of the object
v is the velocity of the object
- On observing the formula we can state that K.E is directly proportional to mass(m) and velocity(v) of the object.
- Obviously, birds have more mass than bees but in question it has given 10 Kg of bees and 10 Kg of birds which means mass is same and also both of them are travelling with same velocity i.e 10m/s and hence both of them will have same kinetic energy(as both of the variables i.e m and v are same).
Result: Both bees and birds have same kinetic energy.
<u>Given:</u>
Moles of gas, n = 1.50 moles
Volume of cylinder, V = 15.0 L
Initial temperature, T1 = 100 C = (100 + 273)K = 373 K
Final temperature, T2 = 150 C = (150+273)K = 423 K
<u>To determine:</u>
The pressure ratio
<u>Explanation:</u>
Based on ideal gas law:
PV = nRT
P= pressure; V = volume; n = moles; R = gas constant and T = temperature
under constant n and V we have:
P/T = constant
(or) P1/P2 = T1/T2 ---------------Gay Lussac's law
where P1 and P2 are the initial and final pressures respectively
substituting for T1 and T2 we get:
P1/P2 = 373/423 = 0.882
Thus, the ratio of P2/P1 = 1.13
Ans: The pressure ratio is 1.13
