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Alex17521 [72]
3 years ago
11

Simplify: (-5a³-7a² +3)+(-9a³ +5a² +9)​

Mathematics
1 answer:
DedPeter [7]3 years ago
3 0

Answer: =−14a3−2a2+12

Step-by-step explanation:

−5a3−7a2+3−9a3+5a2+9

=−5a3+−7a2+3+−9a3+5a2+9

Combine Like Terms:

=−5a3+−7a2+3+−9a3+5a2+9

=(−5a3+−9a3)+(−7a2+5a2)+(3+9)

=−14a3+−2a2+12

Answer:

=−14a3−2a2+12

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For 100​ births, P(exactly ​girls) and ​P( or more ​girls). Is girls in 100 births a significantly high number of​ girls? Which
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Answer;

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Step-by-step explanation:

The complete question is as follows;

For 100 births, P(exactly 56 girls = 0.0390 and P 56 or more girls = 0.136. Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question? Consider a number of girls to be significantly high if the appropriate probability is 0.05 or less V so 56 girls in 100 birthsa significantly high number of girls because the relevant probability is The relevant probability is 0.05

Solution is as follows;

Here. we want to know which of the probabilities is relevant to answering the question and also if 56 out of a total of 100 is sufficient enough to provide answer to the question.

Now, to answer this question, it would be best to reach a conclusion or let’s say draw a conclusion from the given information.

The relevant probability is 0.136 so the value of 56 girls in 100 births is not a significantly high number of girls because the relevant probability is greater than 0.05

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