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3 years ago

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in 2003, the population of Zimbabwe was about 12.6 million people, in which is 1 million more than 4 times the population in 195

0. write and solve an equation to find the approximate population p of Zimbabwe in 1950

1 answer:

Dmitry_Shevchenko [17]3 years ago

4 0

a= 2002 population

x= 1950 population

a=x*4+1,000,000

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Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$

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Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

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8 0

4 years ago

Vika [28.1K]

Answer:

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

Step-by-step explanation:

Given equations are:

4x + 5y = 10

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The general form of linear equation in two variables is given by:

$ax+by = c$

Here a, b and c are constants and x,y are variables.

In the given equations, after comparing with the general form

$a_1 = 4\\b_1 = 5 \\c_1 = 10\\a_2 = A\\b_2 =B\\c_2 = 16$

"In order for a system of equations to have infinity many solutions,

$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$ "

Putting the values we get

$\frac{4}{A} = \frac{5}{B} = \frac{10}{16}\\\frac{4}{A} = \frac{5}{B} = \frac{5}{8}\\Now\\\frac{4}{A} = \frac{5}{8}\\\frac{A}{4} = \frac{8}{5}\\A = \frac{8}{5} * 4\\A = \frac{32}{5}\\And\\\frac{5}{B} = \frac{5}{8}\\\frac{B}{5} = \frac{8}{5}\\B = 8$

Hence,

For A = 32/5 and B = 8 the system of equations will have infinitely many solutions.

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3 years ago

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vovikov84 [41]

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