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Flauer [41]
3 years ago
9

Solve the equation y=2x^2-x-6 using the quadratic formula show the steps to solving

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

x1 = 2 \\ x2 =  -  \frac{3}{2}

Step-by-step explanation:

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}  \\ x =  \frac{1 +  -  \sqrt{ {( - 1)}^{2} - 4(2)( - 6) } }{2(2)}  \\ x =  \frac{1 +  -  \sqrt{1  + 48} }{4}  \\ x =  \frac{1 +  -  \sqrt{49} }{4}  \\ x =  \frac{1 +  - 7}{4}  \\  \\ x1 =  \frac{1  + 7}{4}  =  \frac{8}{4}  = 2 \\ x2 =  \frac{1 - 7}{4}  =   - \frac{6 }{4}  =  -  \frac{3}{2}

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Factoring quadratics 4x^2-13x+3=0
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Answer:

X=3,1/4

Step-by-step explanation:

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Please help me with both problems thank you so much!!
motikmotik
The one on the left is -5/6
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Solve the system of equations two ways: 3x+y=5 and x-2y=4 A) using substitution B) using elimination
Vedmedyk [2.9K]
A. solve for 1 variable
let's solve for x in 2nd equation
add 2y to both sides
x=2y+4
sub 2y+4 for x in other equation
3(2y+4)+y=5
6y+12+y=5
7y+12=5
minu12 both sides
7y=-7
divide 7
y=-1
sub back
x=2y+4
x=2(-1)+4
x=-2+4
x=2
(2,-1)


B. eliminate
eliminate y's
multiply first equation by 2 and add to first

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<u>x-2y=4 +</u>
7x+0y=14

7x=14
divide by 7
x=2
sub back
x-2y=4
2-2y=4
minus 2
-2y=2
divide -2
y=-1
(2,-1)



(2,-1) is answer
5 0
3 years ago
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