Translating that problem into an equation with x as a variable we get 3x + x +10 = 22. Combine like terms to get 4x + 10 = 22. Subtract 10 on both sides to get 4x = 12. Divide by 4 on both sides to get x = 3.
Now to plug in. The first number was represented by 3x. So substituting 3 for the x we get 3(3) = 9. And again for the second number represented by x+10, 3+10 = 13.
Your numbers are 9 and 13. To check just add them together. 13 + 9 is 22, I'll save ya the effort.
-8a^8b^-2/10a^-4b^-10
= (-8/10) a^(8+4)b^(-2+10)
= -4/5 a^12 b^8
=-4 a^12 b^8 / 5
Answer is A.) -4 a^12 b^8 / 5
Answer:
Step-by-step explanation:
a) 4x² + 20 = 0
4x² = -20
x² = -20/4
x² = -5 = i² *5
x = √i²5
x = i√5
b) 4x² + 5 = -7
4x² = -7 - 5
4x² = - 12
x² = -12/4
x² = -3 = 3i²
x = i√3
c) x² + 4x + 20 = 0
a = 1 ; b =4 ; c =20
= (-2 +4i) & -12/2
= (-2 + 4i) and (-6)