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Flauer [41]
4 years ago
9

Solve the equation y=2x^2-x-6 using the quadratic formula show the steps to solving

Mathematics
1 answer:
saul85 [17]4 years ago
7 0

Answer:

x1 = 2 \\ x2 =  -  \frac{3}{2}

Step-by-step explanation:

x =  \frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}  \\ x =  \frac{1 +  -  \sqrt{ {( - 1)}^{2} - 4(2)( - 6) } }{2(2)}  \\ x =  \frac{1 +  -  \sqrt{1  + 48} }{4}  \\ x =  \frac{1 +  -  \sqrt{49} }{4}  \\ x =  \frac{1 +  - 7}{4}  \\  \\ x1 =  \frac{1  + 7}{4}  =  \frac{8}{4}  = 2 \\ x2 =  \frac{1 - 7}{4}  =   - \frac{6 }{4}  =  -  \frac{3}{2}

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If (tan^3 theta -1) / (tan theta - 1) - sec^2 theta +1 = 0, find cot theta.
stiv31 [10]
Hey there !

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The sum of 2 numbers is 22. three times one number is equal to ten more than the other. find the numbers
qwelly [4]
Translating that problem into an equation with x as a variable we get 3x + x +10 = 22. Combine like terms to get 4x + 10 = 22. Subtract 10 on both sides to get 4x = 12. Divide by 4 on both sides to get x = 3. 

Now to plug in. The first number was represented by 3x. So substituting 3 for the x we get 3(3) = 9. And again for the second number represented by x+10, 3+10 = 13. 

Your numbers are 9 and 13. To check just add them together. 13 + 9 is 22, I'll save ya the effort. 
8 0
4 years ago
What is the quotient of -8a^8b^-2/10a^-4b^-10 in simplified form? Assume a=0 b=0 A.) -4a^12b^8/5 B.)-4a^32b^5/5 C.)a^12b^8/80 D.
Naily [24]

-8a^8b^-2/10a^-4b^-10

= (-8/10) a^(8+4)b^(-2+10)

= -4/5 a^12 b^8

=-4 a^12 b^8 / 5

Answer is A.) -4 a^12 b^8 / 5

4 0
3 years ago
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D divided bye 1.4=2.3 what is d
kati45 [8]
Multiply 2.3 by 1.4= D
4 0
3 years ago
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Pls i need this today help me
kondaur [170]

Answer:

Step-by-step explanation:

a) 4x² + 20 = 0

          4x² = -20

            x² = -20/4

            x² = -5 = i² *5

             x = √i²5

            x = i√5

b) 4x² + 5 = -7

        4x² = -7 - 5

       4x² = - 12

          x² = -12/4

         x² = -3 = 3i²

        x = i√3

c) x² + 4x + 20 = 0

a = 1 ; b =4  ; c =20

x = \frac{-b+\sqrt{b^{2}-4ac}}{2a} and \frac{-b-\sqrt{b^{2}-4ac}}{2a};\\\\x = \frac{-4+\sqrt{16-4*1*20}}{2*1} and\frac{-4-\sqrt{16-4*1*20}}{2*1}\\\\=\frac{-4+\sqrt{16-80}}{2}  and \frac{-4-\sqrt{16+80}}{2}\\\\=\frac{-4+\sqrt{-64}}{2}    and  \frac{-4-\sqrt{64}}{2}\\\\= \frac{-4+8i}{2}  and\frac{-4-8}{2}

  = (-2 +4i)  & -12/2

  = (-2 + 4i) and (-6)  

5 0
3 years ago
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