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Firlakuza [10]
4 years ago
14

You randomly select k integers between 1 and 100, inclusive. What is the smallest k that guarantees that at least one pair of th

e selected integers will sum to 101? Prove your answer.
Mathematics
1 answer:
vredina [299]4 years ago
6 0

Answer:

51

Step-by-step explanation:

The possible components to sum up to 101 can only be divided into 2 groups, 1 is larger than 50 and the other is less than or equals to 50

For example

50 + 51 = 101

52 + 49 = 101

60 + 41 = 101

...

99 + 2 = 101

100 + 1 = 101

Therefore, the worst case scenario is to pick all numbers from only 1 group, either all number less than or equal to 50, which there are 50 of them from 1 to 50, or greater than 50, which there are 50 of them from 51 to 100.

So k has to be at least 51 to guarantee that at least one pair of the selected integers will sum to 101

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Plz help me!!
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Answer:

You should circle:

15, 17, 19, 24, 25, 26, 28

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11

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15

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17

|17 - 20.4| = 3.4 < 7.9

17 is within 1 standard deviation of the mean.

19

|19 - 20.4| = 1.4 < 7.9

19 is within 1 standard deviation of the mean.

24

|24 - 20.4| = 3.6 < 7.9

24 is within 1 standard deviation of the mean.

25

|25 - 20.4| = 4.6 < 7.9

25 is within 1 standard deviation of the mean.

26

|26 - 20.4| = 5.6 < 7.9

26 is within 1 standard deviation of the mean.

28

|28 - 20.4| = 7.6 < 7.9

28 is within 1 standard deviation of the mean.

33

|33 - 20.4| = 12.6 > 7.9

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