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2 years ago

Is f = 2 a solution to the inequality below?

Mathematics

2 answers:

vazorg [7]2 years ago

4 0

Answer:

No because if you plug in f with 2 it is saying 2 is less than 1 which is not true so it would be

lana66690 [7]2 years ago

3 0

Answer: no

Step-by-step explanation: 2 is not less than 1

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Please i need help asap!!

chubhunter [2.5K]

Answer:

(-4,-1) is the answer to this.

7 0

2 years ago

Name the kind or kinds of symmetry the following figure has: point, line, plane, or none. (Select all that apply.).

Marina CMI [18]

Answer:

line

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

PLEASE ANSWER WILL MARK BRAINLIEST

zepelin [54]

Answer:

Proof with Statement and Reason is below.

Step-by-step explanation:

Given:

In The Figure

BF ⊥ AC,CE ⊥ AB

To Prove:

Δ ACE ≅ Δ ABF

Proof:

In Δ ACE and Δ ABF

STATEMENT REASONS

1. BF ⊥ AC,CE ⊥ AB Given

2. m∠ BFA = 90°,m∠ CEA = 90° { Perpendicular Lines BF ⊥ AC,CE ⊥ AB }

3. AE = FA Given

4. m∠ A = m∠ A {Reflexive property}

5. Δ ACE ≅ Δ ABF By AAS Congruence Postulate

8 0

3 years ago

8(t+2)-3 (t-4)=6 (t-7)+8

Zarrin [17]

8t+16-3t+12=6t-42+8

5t+28=6t-34

28=t-34

t=62

3 0

3 years ago

Calculate the length of AB using Sine rule

vovikov84 [41]

Answer:

Approximately $22.2\; \rm m$ .

Step-by-step explanation:

By sine rule, the length of each side of a triangle is proportional to the sine value of the angle opposite to that side. For example, in this triangle $\triangle ABC$ , angle $\angle A$ is opposite to side $BC$ , while $\angle C$ is opposite to side $AB$ . By sine rule, $\displaystyle \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C}$ .

It is already given that $BC = 22.4\; \rm m$ and $\angle A = 58^\circ$ . The catch is that the value of $\angle C$ needs to be calculated from $\angle A$ and $\angle B$ .

The sum of the three internal angles of a triangle is $180^\circ$ . In $\triangle ABC$ , that means $\angle A + \angle B + \angle C = 180^\circ$ . Hence,

$\begin{aligned}\angle C &= 180^\circ - \angle A - \angle B \\ &= 180^\circ - 58^\circ - 65^\circ \\ &= 57^\circ\end{aligned}$ .

Apply the sine rule:

$\begin{aligned} & \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C} \\ \implies & AB = \frac{BC}{\sin{\angle A}} \cdot \sin \angle C \end{aligned}$ .

$\begin{aligned}AB &= \frac{BC}{\sin{\angle A}} \cdot \sin \angle C \\ &= \frac{22.4\; \rm m}{\sin 58^\circ} \times \sin 57^\circ \\ &\approx 22.2\; \rm m\end{aligned}$ .

5 0

2 years ago