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kakasveta [241]
3 years ago
10

Describe the motion of a particle with position (x, y) as t varies in the given interval. (For each answer, enter an ordered pai

r of the form x, y.) x = 1 + sin(t), y = 3 + 2 cos(t), π/2 ≤ t ≤ 2π
Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating t in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity:

\cos^{2} t + \sin^{2} t = 1 (1)

Where:

\cos t = \frac{y-3}{2} (2)

\sin t = x - 1 (3)

By (2) and (3) in (1):

\left(\frac{y-3}{2} \right)^{2} + (x-1)^{2} = 1

\frac{(x-1)^{2}}{1}+\frac{(y-3)^{2}}{4} = 1 (4)

The motion of the particle describes an ellipse.

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galben [10]

Answer:

(r-c)(r?c) represents speed

Step-by-step explanation:

we know formula of distance

s=vt

if we exclude t from it then it remains only speed v

same in the case t(r-c)t(r?c)  when we excludes t

then it remains  (r-c)(r?c) which is equal to speed

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7 0
4 years ago
Read 2 more answers
F (x) = 2 (x + 1)^2 - 1
Ivenika [448]

Answer:

Equation: y = x²

  • (-2, 4)
  • (0, 0)
  • (2, 4)

Equation: f(x) = 2(x + 1)² - 1

  • (-2, 1)
  • (0, 1)
  • (2, 17)

Step-by-step explanation:

Equation: y = x²

  • when x = -2, y = (-2)² = 4 ⇒ (-2, 4)
  • when x = 0, y = (0)² = 0 ⇒ (0, 0)
  • when x = 2, y = (2)² = 4 ⇒ (2, 4)

Equation: f(x) = 2(x + 1)² - 1

f(-2) = 2(-2 + 1)² - 1

      = 2(-1)² - 1

      =2(1) - 1

     = 1

Therefore, (-2, 1)

f(0) = 2(0 + 1)² - 1

     = 2(1)² - 1

      =2(1) - 1

     = 1

Therefore, (0, 1)

f(2) = 2(2 + 1)² - 1

     = 2(3)² - 1

      =2(9) - 1

     = 17

Therefore, (2, 17)

5 0
3 years ago
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liberstina [14]
It is -728700 is my answer


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Answer:

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Step-by-step explanation:

2x - 2y = 10

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substitute for x:

2(7) - 2y = 10

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subtract 14 from each side of the equation:

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divide both sides by -2:

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7 0
3 years ago
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