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Contact [7]
3 years ago
8

V over 4 minus 3 equals 5, what does v equal?

Mathematics
1 answer:
Lyrx [107]3 years ago
6 0

Answer:

32

Step-by-step explanation:

v/4 -3=5

       +3 so the 3's cancel out

v/4=8

x4      x4

v=32

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Is it possible for a simple, connected graph that has n vertices all of different degrees? Explain why or why not.
ryzh [129]

Answer:

It isn't possible.

Step-by-step explanation:

Let G be a graph with n vertices. There are n possible degrees: 0,1,...,n-1.

Observe that a graph can not contain a vertice with degree n-1 and a vertice with degree 0 because if one of the vertices has degree n-1 means that this vertice is adjacent to all others vertices, then the other vertices has at least degree 1.

Then there are n vertices and n-1 possible degrees. By the pigeon principle there are two vertices that have the same degree.

8 0
2 years ago
Solving a _____ is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side length
Ray Of Light [21]
ANSWER

C) Triangle

EXPLANATION

Solving a triangle is the process of calculating unknown side lengths or angle measures of a triangle if certain of the side lengths and/or angle measures are known.

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6 0
3 years ago
Read 2 more answers
Which of the following is a function equivalent to f(x) = 5(1.9)3x?
scoundrel [369]
The answer should be B.

5(6.86x)
7 0
3 years ago
Of the new cars in a car dealer's lot, 1 in 6 are white. Today, 4 cars were sold.
stiks02 [169]
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3 years ago
Use the discriminant to find the number and type of solution for x^2+6x=-9​
likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

\displaystyle \large{D =  {b}^{2}  - 4ac}

First, arrange the expression or equation in ax^2+bx+c = 0.

\displaystyle \large{ {x}^{2}  + 6x =  - 9}

Add both sides by 9.

\displaystyle \large{ {x}^{2}  + 6x + 9 =  - 9 + 9} \\  \displaystyle \large{ {x}^{2}  + 6x + 9 =  0}

Compare the coefficients so we can substitute in the formula.

\displaystyle \large{a {x}^{2}  + bx + c =  {x}^{2}  + 6x + 9 }

  • a = 1
  • b = 6
  • c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

\displaystyle \large{D =  {6}^{2}  - 4(1)(9)} \\  \displaystyle \large{D =  36 - 36} \\  \displaystyle \large{D =  0}

Since D = 0, the type of solution is one real root.

6 0
2 years ago
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