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ad-work [718]
2 years ago
7

Determine the average rate of change, in gallons of gas per year, from 1960 and 1999 and then determine what the result means in

this situation. a. -0.33gal/year; the average fuel consumption per year of a passenger car in the U.S. decreased by a third of a gallon per year. b. 0.33 gal/year; the average fuel consumption per year of a passenger car in the U.S. increased by a third of a gallon per year. c. 2.97 gal/year; the average fuel consumption per year of a passenger car in the U.S. increased by nearly 3 gal/year. d. -2.97 gal/year; the average fuel consumption per year of a passenger car in the U.S. decreased by nearly 3 gal/year.
Mathematics
1 answer:
alisha [4.7K]2 years ago
6 0

Answer:

D-step explanation:

None just guessed

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In ΔUVW, w = 9 cm, v = 2.2 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Alja [10]

Complete Question

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

Answer:

16.5°

Step-by-step explanation:

In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.

We solve using Sine rule formula

a/sin A = b/sin B

We are solving for angle W

∠V=136°

Hence:

22 /sin 136 = 9 /sin W

Cross Multiply

22 × sin W = sin 136 × 9

sin W = sin 136 × 9/22

W = arc sin [sin 136 × 9/2.2]

W = 16.50975°

W = 16.5°

3 0
3 years ago
Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq
Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9

125/18 = b^{1.5}/9

b = (62.5²)^{1/3} = 15.75

8 0
3 years ago
Is 9/10 larger than 13/14
Reptile [31]

Answer:

13/14 is greater

Step-by-step explanation:

Find the lcm for both:

<u>9 x 7 </u>     = <u>63</u>

10 x 7        70

<u>13 x 5 </u>    = <u>65</u>

14 x 5        70

so therefore 13/14 is greater since it has a greater value when finding the lcm

5 0
3 years ago
Please help me now I need the answer to this now please help me please help
Vadim26 [7]

Answer:

Too much please's

Step-by-step explanation:

Please stop begging people to help.

3 0
3 years ago
Read 2 more answers
Find the point on the line y = 2x + 3 that is closest to the origin.
ch4aika [34]
1)We have to make a line perpendicular to y=2x+3, passing through the point (0,0).

y=2x+3   
m=solpe=2

The slope of the line perpedicular to y=2x+3 is m´
m´=-1/m
m´=-1/2

Point slope form:
y-y₀=m(x-x₀)
(0,0)
m=-1/2

y-0=-1/2(x-0)
y=-x/2

Therefore, the line perpendicular to y=2x+3 is y=-x/2.

2)The point on the line y=2x+3 tha is closest to the origin is the point of intersection of the two lines.

y=2x+3
y=-x/2

We can solve this system of equations by equalization method.
2x+3=-x/2
least common multiple=2
4x+6=-x
4x+x=-6
5x=-6
x=-6/5  (=-1.2)

y=-x/2
y=-(-6/5)/2=6/10=3/5    (=0,6)

Therefore: the point of the line y=2x+3 that is closest to the origin is:
 (-1.2 , 0.6)

3 0
3 years ago
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