Complete Question
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Answer:
16.5°
Step-by-step explanation:
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
We solve using Sine rule formula
a/sin A = b/sin B
We are solving for angle W
∠V=136°
Hence:
22 /sin 136 = 9 /sin W
Cross Multiply
22 × sin W = sin 136 × 9
sin W = sin 136 × 9/22
W = arc sin [sin 136 × 9/2.2]
W = 16.50975°
W = 16.5°
Answer:
b = 15.75
Step-by-step explanation:
Lets find the interception points of the curves
36 x² = 25
x² = 25/36 = 0.69444
|x| = √(25/36) = 5/6
thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).
The area of the bounded region is given by the integral

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

125/18 = b^{1.5}/9
b = (62.5²)^{1/3} = 15.75
Answer:
13/14 is greater
Step-by-step explanation:
Find the lcm for both:
<u>9 x 7 </u> = <u>63</u>
10 x 7 70
<u>13 x 5 </u> = <u>65</u>
14 x 5 70
so therefore 13/14 is greater since it has a greater value when finding the lcm
Answer:
Too much please's
Step-by-step explanation:
Please stop begging people to help.
1)We have to make a line perpendicular to y=2x+3, passing through the point (0,0).
y=2x+3
m=solpe=2
The slope of the line perpedicular to y=2x+3 is m´
m´=-1/m
m´=-1/2
Point slope form:
y-y₀=m(x-x₀)
(0,0)
m=-1/2
y-0=-1/2(x-0)
y=-x/2
Therefore, the line perpendicular to y=2x+3 is y=-x/2.
2)The point on the line y=2x+3 tha is closest to the origin is the point of intersection of the two lines.
y=2x+3
y=-x/2
We can solve this system of equations by equalization method.
2x+3=-x/2
least common multiple=2
4x+6=-x
4x+x=-6
5x=-6
x=-6/5 (=-1.2)
y=-x/2
y=-(-6/5)/2=6/10=3/5 (=0,6)
Therefore: the point of the line y=2x+3 that is closest to the origin is:
(-1.2 , 0.6)