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Delicious77 [7]
3 years ago
8

You spend $3.50 on fruit. Apples cost $0.20 each while oranges cost $0.30 each. The equation models the situation, where x is th

e number of apples and y is the number of oranges. Which of the following is not a possible solution in the context of the problem?
a. 1 apple; 11 oranges
b. 11 apples; 1 orange
c. 7 apples; 7 oranges
d. 4 apples; 9 oranges
Mathematics
1 answer:
Licemer1 [7]3 years ago
4 0

Answer:

b. 11 apples; 1 orange

Step-by-step explanation:

We test each option, and see if the total is $3.50(what you spend). If the result is different, it is not a possible solution.

a. 1 apple; 11 oranges

1 apple for $0.20

11 oranges for $0.30 each

0.20 + 11*0.30 = $3.50

Possible solution

b. 11 apples; 1 orange

11 apples for $0.20 each

1 orange for $0.30

11*0.2 + 0.3 = 2.5

Not $3.5, so this is not a possible solution.

This is the answer

c. 7 apples; 7 oranges

7*0.2 + 7*0.3 = $3.5

Possible

d. 4 apples; 9 oranges

4*0.2 + 9*0.3 = $3.5

Possible

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Explanation: 
When we have variables on both sides we look for the coefficient that is lower than the two and reverse the sign. 

Example: 

1x+ 4 = 2x+3 

We reverse 1x sign because it is lower so we will be subtracting

2x-1x = 1x

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We would then solve for x.

<span> 

Let's begin to solve! </span>
Step 1:

You would look for the coefficient or variable that is less and reverse the sign. 

In this question the lower number is -x and so we would reverse the sign to add. 

x+x= 2

Step 2: 
We now have

2x+3 = -5

Step 3: 
We will subtract 3 to -5 to find X

-3+-5= -8

Step 4:
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Divide both sides by two fo find x 

Our answer:

\boxed{x = -4}

-


Summary:

We first looked for the lower coefficient (in this case variable). We then flipped the sign and solved for x. 




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<span>Multiplication takes precedence
</span>Execute the command multiplication bracket

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