Using the z-distribution, a sample size of 180 is needed for the estimate.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is given by:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 98% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.327.
The population standard deviation is of 
, and to find the sample size, we have to solve for n when M = 4.
Hence:
n = 179.03.
Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer might be C hope this helps
Answer: z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80
Step-by-step explanation:
let p be the population proportion of students complete their homework on a daily basis.
As per given , we have
p= 0.72
sample size : n= 80
Sample proportion : 
Test statistic for proportion:
i.e.
i.e.
That is , z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80
Answer:
identify a and b for the hyperbola with equation
Answer:
$25.97
Step-by-step explanation:
2.50+8.75+3+10.25 = 24.50 This is the items be bought and now needs to pay 6% tax.
24.50/100*106 = 25.97
